Answer:
in days
Explanation:
A short term environmental change refers to changes in the environment that happens within a short period of time, for example, flooding, drought, volcanic eruptions etc. In contrast to short term environmental change, long term environmental change takes place over a long period of time hence species have a longer time to adapt to it. Short term environmental changes may or may not be caused by humans. An example of a short term environmental change caused by humans is oil spillage. Short term environmental changes may lead to the the migration of species from the ecosystem.
Short term environmental changes usually occur within a very short time. The greatest time frame in which a short term environmental change can occur is in a matter of days. Only longterm environmental changes span hundreds and thousands of years.
Answer:
249.01 g/mol
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
Explanation:
<u>Step 1: Define</u>
Au(CN)₂
<u>Step 2: Identify</u>
Molar Mass of Au - 196.97 g/mol
Molar Mass of C - 12.01 g/mol
Molar Mass of N - 14.01 g/mol
<u>Step 3: Find MM</u>
Molar Mass of Au(CN)₂ - 196.97 + 2(12.01) + 2(14.01) = 249.01 g/mol
Answer: NaCl>HCl&H2O> N2
Explanation:
NaCl, as an ionic substance has a very high boiling point as expected. However, the boiling points of HCl and H2O depend on the relative concentration of the HCl and water, at 20% HCl, it boils at almost the same temperature as water due to extensive intermolecular hydrogen bonding. N2 comprises only of Vanderwaals forces hence it has the least boiling point.
160 g of SO3 are needed to make 400 g of 49% H2SO4.
<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>
The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:
1 mole of SO3 produces 1 mole of H2SO4
Molar mass of SO3 = 80 g/mol
Molar mass of H2SO4 = 98 g/mol
80 g of SO3 are required to produce 98 og 100%H2SO4
mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3
Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g
Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.
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