Answer:
16.48mL
Explanation:
The following data were obtained from the question:
Initial pressure (P1) = 1 atm
Initial temperature (T1) = 0°C = 0°C + 273 = 273K
Initial volume (V1) = 30mL
Final temperature (T2) = 27°C = 27°C + 273 = 300K
Final pressure (P2) = 2atm
Final volume (V2) =..?
Applying the general gas equation, the final volume of the gas can be obtained as follow:
P1V1/T1 = P2V2/T2
1 x 30/273 = 2 x V2/300
Cross multiply to express in linear form
273 x 2 x V2 = 30 x 300
Divide both side by 273 x 2
V2 = (30 x 300)/(273 x 2)
V2 = 16.48mL
Therefore, the new volume of the gas is 16.48mL
