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timurjin [86]
3 years ago
10

A sample of gas starts at 1.00 atm, 0.00 degrees Celsius, and 30.0 mL. What is the volume if the temperature increases to 27.0 d

egrees Celsius and the pressure increases to 2 atm?
Chemistry
1 answer:
Amanda [17]3 years ago
8 0

Answer:

16.48mL

Explanation:

The following data were obtained from the question:

Initial pressure (P1) = 1 atm

Initial temperature (T1) = 0°C = 0°C + 273 = 273K

Initial volume (V1) = 30mL

Final temperature (T2) = 27°C = 27°C + 273 = 300K

Final pressure (P2) = 2atm

Final volume (V2) =..?

Applying the general gas equation, the final volume of the gas can be obtained as follow:

P1V1/T1 = P2V2/T2

1 x 30/273 = 2 x V2/300

Cross multiply to express in linear form

273 x 2 x V2 = 30 x 300

Divide both side by 273 x 2

V2 = (30 x 300)/(273 x 2)

V2 = 16.48mL

Therefore, the new volume of the gas is 16.48mL

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Answer:

14. B    15. D    16. C     17. B

Explanation:

The spontaneous reaction that occurs when the cell operates is shown below:

2Ag^{+} + Cd_{(s)} ⇒2Ag_{(s)} + Cd^{2+}

We need to select the correct option from the list below for the following questions.

(A) Voltage increases. (B) Voltage decreases but remains > zero. (C) Voltage becomes zero and remains at zero. (D) No change in voltage occurs. (E) Direction of voltage change cannot be predicted without additional information.

14. A 50-milliliter sample of a 2-molar Cd(NO_{3})_{2} solution is added to the left beaker.

If a 50-milliliter sample of a 2-molar Cd(NO_{3})_{2}  solution is added to the left beaker, the voltage decreases but its value remains greater than zero. The correct option is B

15. The silver electrode is made larger.

If the silver electrode is made larger, no change in the value of the voltage since we don't have the idea of the initial value. The correct option is D.

16. The salt bridge is replaced by a platinum wire.

If the salt bridge is replaced by a platinum wire, there will be no passage of electrons because electrons can't pass through a platinum wire. Therefore, the voltage will be zero and remains at zero. The correct option is C.

17. Current is allowed to flow for 5 minutes.

If current is allowed to flow for 5 minutes, the voltage decreases but its value remains greater than zero. The correct option is B.

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3 years ago
What kind of scientist would study how mistletoe harms trees?
posledela

Answer:

Biologist

Explanation:

5 0
4 years ago
How does an atom of one element differ from the atom of another element?
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Explanation:

The atoms of one element differs from the atoms of other elements in terms of the number of protons they contain. This is often taken as the atomic number of such an atom.

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Only nuclear reactions have this capability.

When an atom undergoes nuclear reaction that involves change in number of protons, transmutation occurs and a new atom forms.

8 0
3 years ago
When excess dilute hydrochloric acid was added to sodium sulphite 960 of sulphuric (iv) oxide was produced. calculate the mass o
irakobra [83]

The mass of sodium sulfite that was used will be 1,890 grams.

<h3>Stoichiometric problems</h3>

First, the equation of the reaction:

NaSO_3 + 2HCl --- > NaCl_2 + H_2O + SO_2

The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.

Mole of 960 grams SO2 = 960/64 = 15 moles

Equivalent mole of sodium sulfite that reacted = 15 moles

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More on stoichiometric problems can be found here: brainly.com/question/14465605

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3 0
1 year ago
The heat of reaction for the combustion of propane is –2,045 kJ. This reaction is: C3H8(g) +502 (g) 3CO2 (g) + 4H2O (g). Determi
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Answer:

\Delta _fH_{C_3H_8}=-102.7kJ/mol

Explanation:

Hello,

In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:

\Delta _cH=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-5*\Delta _fH_{O_2}

Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:

\Delta _fH_{C_3H_8}=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-5*\Delta _fH_{O_2}-\Delta _cH\\\\\Delta _fH_{C_3H_8}=3*(-393.5)+4*(-241.8)-5*0-(-2045)\\\\\Delta _fH_{C_3H_8}=-102.7kJ/mol

Best regards.

8 0
3 years ago
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