Answer:
Specific gravity of mineral = 2.6
Explanation:
Given data:
Density of mineral = 2.6 g/cm³
Specific gravity = ?
Solution:
Specific gravity:
Specific gravity of a substance is ration of density of substance and the density of reference substance. It is unit less quantity.
Mostly water is taken as reference substance.
The density of water is 1 g/cm³
Thus the specific gravity of mineral is,
Specific gravity of mineral = density of mineral /density of water
Specific gravity of mineral = 2.6 g/cm³ / 1 g/cm³
Specific gravity of mineral = 2.6
Answer:
C.)Recycled bottles and containers are used to produce lumber products that can be used as an outdoor building material.
Explanation:
I believe the answer is an ion.
Hello!
Data:
P (pressure) = 1 atm
V (volume) = 18.5 L
T (temperature) = 300 K
n (number of mols) = ? (in mol)
R (Gas constant) = 0.082 (atm*L/mol*K)
Apply the data to the Clapeyron equation (ideal gas equation), see:






Note:
If the feedback is to be considered, the closest r
esponse is 0.751 mol Nacl
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I hope this helps. =)