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Bumek [7]
3 years ago
11

What does a slope of 1/4 look like

Mathematics
1 answer:
Reil [10]3 years ago
3 0
Slope is also known as rise over run - 
\frac{rise}{run}
Here, we have the slope \frac{1}{4}. This means that the rise is 1 and the run is 4. Since both values are positive, we can say that we go up one and we go right four. When we plot this on a graph (the graph is attached), we get the same exact formula we found. **In the graph, I plotted the line y= \frac{1}{4} x**. Hope this helped!

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The mean height of married American women in their early twenties is 64.5 inches and the standard deviation is 2.5 inches. The m
SSSSS [86.1K]

Answer:

The equation for regression line and predicting a husband's height for married couples in their early 20s

Equation: Y'=33.67+0.54*X'

Step-by-step explanation:

r=0.5

x'=64.5

Sx=2.5

y'=68.5

Sy=2.7

General regression line equation is:

Y'=a+b*X'

so the slope of the regression line is the linear correlation coefficient multiplied by the standard deviation for y' divided by the standard deviation for x'

b=r*\frac{S_{y}}{S_{x}}\\b=0.5*\frac{2.7}{2.5}\\b=0.54

The intercept with axis y is the mean of the decreased by the product of the slope and the mean of x

a=y'-b*x'\\a=68.5-0.54*64.5\\a=33.67

The equation regression line then is:

Y'=33.67+0.54*X'

4 0
3 years ago
A survey at your school found that 842 in 989 students have a cell phone. What percent of the student in school has a cell phone
Mumz [18]

Answer:

85.14% of the students have a cell phone.

8 0
3 years ago
Read 2 more answers
A bank account has a beginning balance of $560.00. After 6 months, the balance in the account has increased to $572.60. What int
Licemer1 [7]
Interest = $572.60 - $560.00 = $12.60

$560 x 6i/12 = $12.60

i = ($12.60 x 12) / ($560 x 6) = 0.045%
7 0
3 years ago
In 2004, a pine tree was 5 3/4 ft tall. If the tree grew at an average rate of 5/6 ft per year for the next 7 years, how tall wo
Nady [450]

Answer:

11 7/12 ft tall

Step-by-step explanation:

5 3/4 + (5/6*7)

139/12

11 7/12

7 0
4 years ago
Elimination method: ax+by=r, -bx+cy=s
Alex17521 [72]
\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]

Isolate x for ax+by=r

x= \frac{r-by}{a} ; a \neq 0

Subsititute x= \frac{r-by}{a}

-b \frac{r-by}{a} +cy=s

Isolate r for : -b \frac{r-by}{a}+cy=s

r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0

For x : \frac{r-by}{a}

Subsititute r = - \frac{as-acy-b^2y}{b}

x= -\frac{as-acy-b^2y}{b}/a

x =  \frac{cy-s}{b}

The solutions to the system of equations are:

r= -\frac{as-acy-b^2y}{b} and <span> x = \frac{cy-s}{b}
</span>
hope this helps!


3 0
3 years ago
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