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adoni [48]
3 years ago
6

What is the inequality of this graph?

Mathematics
1 answer:
Over [174]3 years ago
7 0

Answer: y < 3x -4

Step-by-step explanation:

We know two points of line: (0,-4) and (1,-1)

Therefore, we can find the slope: 3/1.

We know the y intercept.

Dashed line means the inequality is not apart of the region.

y < 3x-4

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Which expression can be used find the surface area the following triangular prism // 10, 8, 6, 20
coldgirl [10]

Answer:

Step-by-step explanation:

45

3 0
3 years ago
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The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the proba
Olegator [25]

Answer:

The probability that occurrence of 8 in ten minutes is 0.0771.

Step-by-step explanation:

Poisson Distribution:

A discrete random variable X having the enumerable set {0,1,2,.....} as the spectrum, is said to have Poisson distribution with parameter \mu (>0), if the p.m.f is given by

P(X=x)=\frac{e^{-mu}\mu^x}{x!}  for x=0,1,2,...

               = 0,           elsewhere

The mean number of occurrences in ten minutes is 5.3.

Here \mu = 5.3 and x= 8

P(X=8)=\frac{e^{-5.3}(5.3)^8}{8!}

               =0.0771

The probability that occurrence of 8 in ten minutes is 0.0771.

3 0
2 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
2 years ago
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timofeeve [1]
We can't match events with probability if there is no events... do you have the events? 
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3 years ago
If there are 1000 grams in a kilogram and 454 grams in a pound, how many pounds are there per kilogram?
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Per kg, there would be 2.20462 pounds but you can round it
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3 years ago
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