10,000 hours is 600,000 minutes, or 36,000,000 seconds
Before answering these questions, we need to write out both equations.
For Job 'A', his salary would be: 55,000 + 2,500n
This assumes 'n' equals the number of years Lenny spends at these companies.
For Job 'B', his salary would be: 62,000 + 2,000n
A.
So basically we need to find a number were:
55,000 + 2,500n = 62,000 + 2,000n
is true. So basically solve ^that^ equasion.
55,000 + 2,500n = 62,000 + 2,000n
simplify
500n = 7,000
devide
n = 14
Fourteen years is your answer.
B.
a. 55,000 + 2,500n
b. 62,000 + 2,000n
So in order to answer this question, you basically just have to replace 'n' with the number '20', and see which one's bigger.
a.
55,000 + 2,500(20)
55,000 + 50,000
105,000
b.
62,000 + 2,000(20)
62,000 + 40,000
102,000
105,000 > 102,000
So your answer is:
Lenny should go to company 'a' because 105,000 is greater than 102,000.
[[tip: If you want to wow, surprise, or confuse your teacher (depending on her actual intelligence) write something like, 'another reason Lenny should choose company 'a' is because it gives higher annual raises, which is better in long-term.' He/She may not get it though, lol, wrong class.]]
Anyway, I hope this helped! :D
Line CA is a straight line, meaning it adds up to 180°
Line BE splits the line into two supplementary angles, because when the two angles are added together they will equal 180°
Using the rule of supplementary angles, we can then make the equation 3x + 8x + 15 = 180
Now, simplify the equation by combining like terms
11x + 15 = 180
To solve, isolate x
11x + 15 = 180
11x = 165
x = 15
Step-by-step explanation:

Answer:
Union and Intersection
Step-by-step explanation:
We know that the algebra of sets define the properties and laws of the sets.
The basic operations of sets are,
Union, Intersection, Complement of a set and Equality of sets.
Since, the operations addition, subtraction, multiplication and division are the basic arithmetic operations of numbers.
i.e. they are not in the algebra of sets.
So, we get that out of the given options, the operations in algebra of sets are Union and Intersection.