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Roman55 [17]
3 years ago
11

During the winter months, many locations experience snow and ice storms. It is a common practice to treat roadways and sidewalks

with salt, such as CaCO3 . If a 18.1 kg bag of CaCO3 is used to treat the sidewalk, how many moles of CaCO3 does this bag contain?
Chemistry
1 answer:
Temka [501]3 years ago
6 0

Answer:

180.845 mol

Explanation:

Molar mass of Ca: 40,078 g/mol

Molar mass of C: 12,0107 g/mol

Molar mass of O: 15,999 g/mol

Molar mass of CaCO3: (40,078+12,0107+3×15,999) 100,0857 g/mol

The number of moles= mass of bag in g ÷ molar mass of CaCO3

⇒ n= (18.1×1000)÷100,0857 = 180.845 mol

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sineoko [7]

Answer:B

Explanation:

7 0
3 years ago
1. If 3.25 moles of oxygen were consumed, how much moles of carbon dioxide are<br> produced?
liraira [26]

Answer:

3.25 mol CO₂

Explanation:

Step 1: Write the balanced equation

C(s) + O₂(g) ⇒ CO₂(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to CO₂ is 1:1.

Step 3: Calculate the number of moles of CO₂ produced from 3.25 moles of O₂

We will use the previously established molar ratio.

3.25 mol O₂ × 1 mol CO₂/ 1 mol O₂ = 3.25 mol CO₂

8 0
3 years ago
A sealed plastic bag is filled with 1 l of air and has a pressure of 101.3 kpa. You sit on the bag and the pressure increases to
sesenic [268]

Answer:

The answer to your question is   V2 = 0.203 kPa

Explanation:

Data

Volume 1 = V1 = 1l

Pressure 1 = P1 = 101.3 kPa

Volume 2= V2 = ?

Pressure 2 = 500 kPa

Process

- Use the Boyle's law to solve this problem

               P1V1 = P2V2

-Solve for V2

              V2 = P1V1/P2

-Substitution

             V2 = (101.3 x 1) / 500

-Simplification

            V2 = 101.3 / 500

-Result

            V2 = 0.203 kPa

8 0
4 years ago
A 10.0cm3 volume of alcohol has a mass of 7.05g. What is the density of the alcohol in grams per cubic centimeter
ExtremeBDS [4]

Answer:

0.705 g/cm³

Explanation:

Step 1: define density

The (volumetric mass) density of a sample or substance, is this sample or substance its mass per unit volume and can be defined through following formula:

ρ = m/v

with ρ = density (kg/m³)

m = mass of the substance (kg )

v = volume (m3)

Step 2: change datat SI-units

10.0 cm³ = 10^-5 m³

7.05 g = 0.00705 kg

ρ = 0.00705 kg / 10^-5 m³  = 705 kg / m³

To convert this to g/cm³ we have to divide by 1000

ρ = 0.705 g/cm³

To control this we calculate 7.05g / 10cm³ = 0.705 g/cm³

The desnity of the alcohol is 0.705 g/cm³

7 0
4 years ago
What elements,compounds or mixtures that can be broken down into something simpler?
cupoosta [38]

Do you need examples or?

Elements can’t be broken down it’s already the most simplest substance ( eg.oxygen,carbon )- basically your whole periodic table

Compunds can be broken down into elements (eg. carbon dioxide and iron oxide)

Mixtures are just 2 or more compunds chilling with each other and can be broken down (eg. salt and water)
7 0
3 years ago
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