Answer:
0.877 mol
Step-by-step explanation:
We can use the<em> Ideal Gas Law </em>to solve this problem.
pV = nRT Divide both sides by RT
n = (pV)/(RT)
Data:
p = 646 torr
V = 25.0 L
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = 22.0 °C
Calculations:
(a) <em>Convert the pressure to atmospheres
</em>
p = 646 torr × (1 atm/760 torr) = 0.8500 atm
(b) <em>Convert the temperature to kelvins
</em>
T = (22.0 + 273.15) K = 295.15 K
(c) <em>Calculate the number of moles
</em>
n = (0.8500 × 25.0)/(0.082 06 × 295.15)
= 0.877 mol
1. In this reaction, 2 moles of nitrogen gas reacts with 3 moles of oxygen gas to give 2 moles of N2O3 gas. 2 nitrogen molecules react with 3 oxygen molecules to give 2 N2O3 molecules. Under STP, one mole of an ideal gas occupies a volume of 22.4 liters. So in this reaction, 44.8 liters of nitrogen gas reacts with 67.2 liters of oxygen gas to give 44.8 liters of N2O3 gas. The total mass of the reactants (N2 and O2) is the same as the total mass of the product (N2O3). This is called mass balance of a chemical reaction.
2. According to the chemical reaction, 3 moles of chlorine gas produces 2 moles of iron(III) chloride. So, to produce 1 moles of iron(III) chloride, 3/2 (1.5) moles of chlorine gas is required. Therefore, to produce 14 moles of iron(III) chloride, 14 x 1.5 = 21 moles of chlorine is needed.
The answer is the first bubble, it absorbs white light and refracts green, this is because the color you see is the reflection of the object
<h3>
Answer:</h3>
Change in temperature = 2.03°C, the temperature is increasing
<h3>
Explanation:</h3>
- To calculate the quantity of heat absorbed or released by a substance we multiply mass of the substance by it's specific heat capacity and the temperature change.
- Therefore, Quantity of heat, Q = mass × specific heat × change in temperature
In this case;
Mass of water = 30.0 g
Quantity of heat absorbed = 255 J
Specific heat capacity of water = 4.186 J/g°C
Rearranging the formula, Δt = Q ÷ mc
Δt = 255 J ÷ (4.186 J/g°C×30.0 g )
= 2.03 °C
The temperature change is 2.03°C, the temperature is therefore increasing.
