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Rama09 [41]
4 years ago
11

A sealed plastic bag is filled with 1 l of air and has a pressure of 101.3 kpa. You sit on the bag and the pressure increases to

500 kpa. What is the volume of the bag as you are sitting on it? (T is constant)
Chemistry
1 answer:
sesenic [268]4 years ago
8 0

Answer:

The answer to your question is   V2 = 0.203 kPa

Explanation:

Data

Volume 1 = V1 = 1l

Pressure 1 = P1 = 101.3 kPa

Volume 2= V2 = ?

Pressure 2 = 500 kPa

Process

- Use the Boyle's law to solve this problem

               P1V1 = P2V2

-Solve for V2

              V2 = P1V1/P2

-Substitution

             V2 = (101.3 x 1) / 500

-Simplification

            V2 = 101.3 / 500

-Result

            V2 = 0.203 kPa

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What is the mass of a sample of NH3 containing 6.3 × 1024 molecules of NH3?
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