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allochka39001 [22]
3 years ago
11

The cost of oranges in a grocery store is directly proportional to the number of oranges purchased. jerri paid $2.52 for 6 orang

es. if p represents the cost, in dollars, and n represent the number of oranges purchased, which equation best represents this relationship?
A. p = 0.42n
B. P = 2.52n
C. p = 6n
D. p = 15.12n
Mathematics
2 answers:
Pachacha [2.7K]3 years ago
7 0
I think its A because the amount for one orange is .42

kaheart [24]3 years ago
3 0

Answer:

The correct answer is option A

Step-by-step explanation:

Cost of the oranges is directly proportional to the number of oranges

Thus ,

p ∝ n -------------------------- Eq  (A)

p = kn\\

cost of 6 \\ oranges is equal to $ 2.52\\

Cost of 1\\ orange is equal to = \frac{2.52}{6} \\= 0.42\\

Thus, Eq (A) can be re-written as

p = 0.42 n\\

Thus, the correct answer is option A

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A group of 59 randomly selected students have a mean score of 29.5 with a standard
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Answer:

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

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And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

Step-by-step explanation:

Information given

\bar X = 29.5 represent the sample mean

\mu population mean  

s= 5.2 represent the sample standard deviation

n=59 represent the sample size  

Confidence interval

The confidence interval for the true mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=59-1=58

The Confidence interval is 0.90 or 90%, the significance is \alpha=0.1 and \alpha/2 =0.05, and the critical value is t_{\alpha/2}=1.671

Now we have everything in order to replace into formula (1):

29.5-1.671\frac{5.2}{\sqrt{59}}=28.37    

29.5+1.671\frac{5.2}{\sqrt{59}}=30.63    

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

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