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Svetlanka [38]
3 years ago
14

A missile is moving 1350 m/s at a 25° angle it needs to hit a target 23,500 m away in a 55° direction in 10.2 seconds what is th

e magnitude of its final velocity
Physics
1 answer:
Margarita [4]3 years ago
4 0

Answer:

3504 m/s

Explanation:

Let x be the horizontal component of distance

y - vertical component of distance

t-time

ax- horizontal component of acceleration

ay-Vertical component of acceleration

Vx-horizontal component of velocity

Vy-Vertical component of velocity

horizontally: x = V_x ×t + ½×a_x×t²  

plugging the values we get

23500× cos 55º = 1350×cos25.0º × 10.20 + ½×a_x× (10.20)²  

⇒ax = 19.2 m/s²  

Moreover,

V'x = V_x + a_x×t = 1350×cos25.0º + 19.2×10.20= 1419 m/s  

similarly in vertical direction:

y = V_y×t + ½×a_y×t²  

23500×sin55º = 1350×sin25.0º×10.20s + ½×a_y×(10.20)²  

⇒a_y = 258 m/s²  

Also,

V'y = V_y + a_y×t = 1350×sin25.0º + 258×10.20 = 3204 m/s  

Therefore

V = √(V'x² + V'y²) = 3504 m/s  

therefore,  magnitude of final velocity of missile=3504 m/s

THANKS  

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b

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Explanation:

From the question we are told that the

       The magnitude of electric field is E = 5000N/C

        The number of proton is  N_p = 1*10^{15}

        The distance between the plates is  d = 5cm = \frac{5}{100} = 0.05m

The total charge can be mathematically represented as

            q = N_p * e

Where e is the charge on one proton which has a value of =1.6*10^{-19}C

      Substituting values

           q = 1 *10^{15} * 1.6*10^{-19} = 1.6 *10^{-4}C

The change in potential energy is mathematically represented ads

         \Delta U = -(qE)d

where the negative sign shows that the work done by the electric force is against the electric field

                Substituting values

         \Delta U = - 1.6*10^{-4} * 5000 * 0.05

                = -4*10^{-2}J

 

   The mass of the bead is given as 0.05kg

  The change in potential due to gravity is mathematically given as

                    \Delta U = -mgh

the negative sign is  due to the fact that the height is decreasing

And g =9.8m/s^2

                  Making h the subject

        h = \frac{\Delta U}{mg}

Substituting values

                 h = \frac{4*10^{-2}}{0.05 * 9.8}

                   =0.081m = 0.082 *100 = 8.2cm

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