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aleksklad [387]
3 years ago
15

A train station bell gives off a fundamental tone of 500 Hz as the train approaches the station at a speed of 30.0 m/s. If the s

peed of sound in air is 339 m/s, what will be the apparent frequency of the bell to an observer riding the train?
Physics
1 answer:
TiliK225 [7]3 years ago
3 0

Answer:

548.5 Hz

Explanation:

We are given that

Frequency of source=500 Hz

Speed of train=30m/s

Speed of sound in air=339m/s

We have to find the frequency of the bell to an observer riding the train.

The apparent frequency for the listener

f=\frac{v_0}{v_0-v_s}f_1

Where f_1=Frequency of source

v_0=Speed of sound

v_s=Speed of source

Using the formula

The apparent frequency of the bell to an observer riding the train=\frac{339}{339-30}\times 500=548.5 Hz

Hence, the apparent frequency of the bell to an observer riding the train=548.5 Hz

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An object is moving in a straight line with a constant acceleration. Its position is measured at three different times, as shown
stiv31 [10]

The constant acceleration of the object is 0.414\ m/s^2.

<h3>Acceleration of the object</h3>

The acceleration of the object is constant, and the values at the three different positions is the same.

<h3> For the first position and time</h3>

s = v_0 t + \frac{1}{2} at^2\\\\37.7 = v_o(9.6) +\frac{1}{2} a(9.6)^2\\\\ 37.7 = 9.6v_0 + 46.08a

<h3>For the second position and time</h3>

39.3 = v_o(18.048) +\frac{1}{2} a(18.048)^2\\\\ 39.3 = 18.048v_0 + 162.87a

<h3>Solve the first and second equation together</h3>

37.7 = 9.6v_0 + 46.08a\\\\39.3 = 18.048v_0 + 162.87a\\\\18.048: \ \  680.41 = 173.261v_0 + 831.651a\\\\9.6: \ \ \ \  -(377.28 = 173.261 v_0+ 1563.552a)\\------------------\\303.13 = -731.901a\\\\-a = \frac{303.13}{731.901} \\\\-a = 0.414 \ m/s^2\\\\|a| = 0.414 \ m/s^2

Thus, the constant acceleration of the object is 0.414\ m/s^2.

Learn more about acceleration here: brainly.com/question/14344386

4 0
1 year ago
A book with mass 2.3 kg sits on a table. What is the normal force on the
natita [175]

Explanation:

The table is level and there are no other forces on the book, so the normal force is equal to the weight.

N = mg

N = (2.3 kg) (9.8 m/s²)

N = 22.5 N

6 0
3 years ago
Read 2 more answers
A point charge of 6.0 nC is placed at the center of a hollow spherical conductor (inner radius = 1.0 cm, outer radius = 2.0 cm)
egoroff_w [7]

Explanation:

The given data is as follows.

             q = 6.0 nC = 6 \times 10^{-9} C

         inner radius (r) = 1.0 cm = 0.01 m   (as 1 cm = 100 m)

So, there will be same charge on the inner surface as the charge enclosed with an opposite sign.

Formula to calculate the charge density is as follows.

            \sigma = \frac{q_{in}}{A} .......... (1)

Since, area of the sphere is as follows.

               A = 4 \pi r^{2} ........... (2)

Hence, substituting equation (2) in equation (1) as follows.

      \sigma = \frac{q_{in}}{4 \pi r^{2}}

                   = \frac{6 \times 10^{-9} C}{4 \times 3.14 \times (0.01)^{2}}            

                   = 0.477 \times 10^{-5}

or,               = 4.77 \mu C/m^{2}

Thus, we can conclude that the resulting charge density on the inner surface of the conducting sphere is 4.77 \mu C/m^{2}.

5 0
2 years ago
What is a type of material that tries to prevent the flow of thermal energy?
Citrus2011 [14]
A type of material that tries to prevent the flow of thermal energy is called an insulator.
4 0
3 years ago
The standard wave format for any wave is wave. When depicting wave in standard wave format, the direction of motion must be rota
german

Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

  • An inverted wave is a wave in which the vibrations of the particles are perpendicular to the direction of wave motion.
  • Longitudinal waves, on the other hand, are waves in which the vibrations of the particles are parallel to the direction of wave motion.
  • Electromagnetic waves are waves that do not require medium media for transmission, including radio waves, microwaves, UV lights, etc.
  • Most electromagnetic waves are transverse in nature.
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