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aleksklad [387]
3 years ago
15

A train station bell gives off a fundamental tone of 500 Hz as the train approaches the station at a speed of 30.0 m/s. If the s

peed of sound in air is 339 m/s, what will be the apparent frequency of the bell to an observer riding the train?
Physics
1 answer:
TiliK225 [7]3 years ago
3 0

Answer:

548.5 Hz

Explanation:

We are given that

Frequency of source=500 Hz

Speed of train=30m/s

Speed of sound in air=339m/s

We have to find the frequency of the bell to an observer riding the train.

The apparent frequency for the listener

f=\frac{v_0}{v_0-v_s}f_1

Where f_1=Frequency of source

v_0=Speed of sound

v_s=Speed of source

Using the formula

The apparent frequency of the bell to an observer riding the train=\frac{339}{339-30}\times 500=548.5 Hz

Hence, the apparent frequency of the bell to an observer riding the train=548.5 Hz

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Suppose that you are standing on a train accelerating at 0.20g (where g is the acceleration due to gravity). What minimum coeffi
prisoha [69]

Answer:

0.2

Explanation:

The given parameters are;

The acceleration of the train, a = 0.2·g

The mass of the person standing on the train = m

Let μ represent the coefficient of static friction, we have;

The force acting on the person, F = m × a = m × 0.2·g

The force of friction acting between the feet and the floor, F_f = m·g·μ

For the person not to slide we have;

The force acting on the person = The force of friction acting between the feet and the floor

F = F_f

∴ m × 0.2·g = m·g·μ

From which we get;

0.2 = μ

The coefficient of static friction that must exist between the feet and the floor if the person is not to slide, μ = 0.2.

7 0
2 years ago
Can someone help me?!!!!!
german
<h2>Hello!</h2>

The answer is:

The first option,  the walker traveled 360m more than the actual distance between the start and the end points.

Why?

Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).

So, calculating we have:

Traveler:

Distance=NorthCoveredDistance+EastCoveredDistance

Distance=4*180m+3*180m=720m+540m=1260m

Actual distance between the start and the end point (displacement):

ActualDistance=\sqrt{NorthDistance+EastDistance}\\\\ActualDistance=\sqrt{NorthDistance^{2} +EastDistance^{2}}\\\\ActualDistance=\sqrt{(720m)^{2} +(540m)^{2}}\\\\ActualDistance=\sqrt{518400m^{2} +291600m^{2}}\\\\ActualDistance=\sqrt{810000m^{2}}=900m

Now, to calculate how much farter did the traveler walk, we need to use the following equation:

DistanceDifference=WalkerCoveredDistance-ActualDistance\\\\DistanceDifference=1260m-900m=360m

Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.

Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.

Have a nice day!

3 0
3 years ago
Which planet has the most gravity and why
djyliett [7]

heya mate

the planet Jupiter has most gravity due to its size

7 0
3 years ago
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An applied force of 50 N is used to accelerate an object, that weighs 73 N, to the right across a frictional surface. The object
Hunter-Best [27]

Answer:

5.38 m/s^2

Explanation:

NET force causing the object to accelerate  =  50 -10 = 40 N

Mass of the object =  73 N / 9.81 m/s^2 = 7.44 kg

F = ma

40 = 7.44 * a         a = 5.38 m/s^2

6 0
1 year ago
The scientific law that the physical universe is gradually becoming dissipated and disordered is called _____. entropy uniformit
ch4aika [34]
It is called entropy
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3 years ago
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