Rust is a chemical all the others are physical changes
We're adding two vectors here. The first is 300 Newtons to the right, which we can write as (300, 0), meaning 300 to the right, 0 up.
The second is 300 at let's say a 45 degree angle down. For the components we have an isosceles right triangle with hypotenuse 300, so the components are both magnitude 300/√2 = 150√2. So we can write this vector (150√2, -150√2), the negative sign because it points down in the y direction.
Adding is componentwise. The resulting force is (300+150√2, -150√2).
That has square magnitude
r² = (300+150√2)² + (-150√2)² = 150² ( (2+√2)² + (√2)² )
= 150²( (6 + 4√2) + 2)
= 300²(2+√2)
so
r = 300 √(2+√2) Newtons
That's the answer; I'm not sure if your class expects a calculator approximation, which is 554.3 Newtons.
Explanation:
Force=Mass*acceleration or F=MA. To find acceleration can be rewritten as A=F/M. If you input the numbers ypu can rewrite as A= 10N/5kg, A=2
The acceleration is 2 meters per sec.
Answer:
I could be wrong but I think it is 560 W
