Answer:
2.5L [NaCl] concentrate needs to be 4.8 Molar solution before dilution to prep 10L of 1.2M KNO₃ solution.
Explanation:
Generally, moles of solute in solution before dilution must equal moles of solute after dilution.
By definition Molarity = moles solute/volume of solution in Liters
=> moles solute = Molarity x Volume (L)
Apply moles before dilution = moles after dilution ...
=> (Molarity X Volume)before dilution = (Molarity X Volume)after dilution
=> (M)(2.5L)before = (1.2M)(10.0L)after
=> Molarity of 2.5L concentrate = (1.2M)(10.0L)/(2.5L) = 4.8 Molar concentrate
If we takes 11. 2 kj of energy to raise the temperature of 145 g of benzene from 23. 0°c to 68. 0°c, then the specific heat of benzene is
1716.475 J/kg.°C.
Specific Heat capacity is given as
Q = cm(t₂-t₁) ................
Where Q = quantity of heat, c = specific heat of benzene, m = mass of benzene, t₁ = initial temperature, t₂ = final temperature.
=
Given:
Substitute into equation 2.
Hence the specific heat of benzene =
Learn more about specific heat: brainly.com/question/21041726
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If you keep an egg in salt for too long.....it might form a stronger shell because salt helps fill up the cracks....but I have no idea. =\