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pogonyaev
3 years ago
11

Any help would be nice

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0

Answer:

I think it's C.

Step-by-step explanation:

A. and D. don't make any sense so I assume they're incorrect. B. just seems wrong also by a small margin.

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Xx is 25% of 104, 7 is 10% of yy, and nn is 80% of yy. yy is what percent of (n+y−x)(n+y−x)?
Natali5045456 [20]
X = 0.25×104 =26
y = 7 × 10 = 70
n = 70 × 0.8 = 56

(56+70-26)(56+70-26)
⇒(100)(100) = 100

\frac{70}{1000} × 100 = 7%
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2 years ago
Determine whether the LCM for all pairs of odd numbers is ​sometimes​, ​always​, or never​ their product. Explain.
allochka39001 [22]
The lcm of all pairs of odd numbers is sometimes their product. Some examples:
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3 years ago
Order of the set of numbers from least to greatest : Square root of 64, 8 1/7,8.14...,15/2 please help
KIM [24]

Answer:

15 /2 ,  Square root of 64, 8.14, 8 1/7

4 0
2 years ago
What is the basic ratio for 30:42
lianna [129]
30:42 is represented as 30/42
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3 years ago
Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number
Triss [41]

Answer:

By definition, the derivative of f(x) is

lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

Let's use the definition for f(x)=\frac{1}{x}

lim_{h\rightarrow 0} \frac{\frac{1}{x+h}-\frac{1}{x}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{x-(x+h)}{x(x+h)}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{(-1)h}{x^2+xh}}{h}=\\lim_{h\rightarrow 0} \frac{(-1)h}{h(x^2+xh)}=\\lim_{h\rightarrow 0} \frac{-1}{x^2+xh)}=\frac{-1}{x^2+x*0}=\frac{-1}{x^2}

Then, f'(x)=\frac{-1}{x^2}

7 0
3 years ago
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