<span>A. H(w) gets very large. </span>
Step-by-step explanation:
1.Get the equation in the form y = ax2 + bx + c.
2.Calculate -b / 2a. This is the x-coordinate of the vertex.
3.To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.
Hi there!
We can use right-triangle trigonometry to solve.
We are given the HYPOTENUSE and ADJACENT sides, so we must use cosine in this instance.
cosθ = Adjacent/Hypotenuse
We can plug in what is given:
cos(28) = A/17
Solve for 'A':
17cos(28) = <u>15.01 ft</u>
First factor (x square -36), the answer will be (x+6)(x-6).
Second, cancel the x .
6x/ (x+6)(x-6)
4x/(6)(-6)
4x/-36
