Use the sum-product pattern
2
−
−
1
2
x
2
−
x
−
12
x2−x−12
2
+
3
−
4
−
1
2
x
2
+
3
x
−
4
x
−
12
x2+3x−4x−12
2
Common factor from the two pairs
2
+
3
−
4
−
1
2
x
2
+
3
x
−
4
x
−
12
x2+3x−4x−12
(
+
3
)
−
4
(
+
3
)
x
(
x
+
3
)
−
4
(
x
+
3
)
x(x+3)−4(x+3)
3
Rewrite in factored form
(
+
3
)
−
4(+3)x
(x+3)−4(x+3)
x(x+3)−4(x+3)
(−4)(+3)
(x−4)(x+3)
(x−4)(x+3)
The value of the z statistic for the considered data is given by: Option A: -3.87 approximately.
<h3>How to find the z score (z statistic) for the sample mean?</h3>
If we're given that:
- Sample mean =
- Sample size = n
- Population mean =
- Sample standard deviation = s
Then, we get:
If the sample standard deviation is not given, then we can estimate it(in some cases) by:
where 
population standard deviation
For this case, we're specified that:
- Sample mean = = 2.3
- Sample size = n = 15
- Population mean = = 2.7
- Population standard deviation = = 0.4
Thus, the value of the z-statistic is evaluated as:
Thus, the value of the z statistic for the considered data is given by: Option A: -3.87 approximately.
Learn more about z statistic here:
brainly.com/question/27003351
Answer:
Step-by-step explanation:
A. distribute the X to the X in the parenthesis and you get 2x. Then distribute the X to the -7 in the parenthesis and you get -7x. Combine like terms so that would be 2x-7x and you get -5x.
C. distribute the 6x to the X in the parenthesis and you get 7x. Then distribute the 6x to the 2 in parenthesis and you get 8x. Combine like terms so that would be 7x+8x and you get 15x.
E. Not sure on this one, sorry.
Answer:
The standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 175760000
Step-by-step explanation:
If there are no restrictions, all numbers and letters are available to be used then. And with no restrictions, every number or letter can appear more than once.
There are 7 spaces available; 3 spaces for letters, 4 spaces for numbers
The different combination of letters and numbers then becomes,
26 × 26 × 26 × 10 × 10 × 10 × 10
This is because, all 26 letters (A to Z) can occupy the first space, the second space and the third space. And all 10 digits (0 to 9) can occupy the fourth space, the fifth space, the sixth space and the seventh space.
So, the standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 26 × 26 × 26 × 10 × 10 × 10 × 10 = 175760000 different standard issue license plates.
$6.93
you just multiply $99 by .07 since that’s the percentage
