24 Points!! 12 Points Each Please Help ASAP!! View Attached Image!! Will Mark Brainliest If All Are Answered!!

Consider the following reaction: CHCl3(g) + Cl2(g) → CCl4(g) + HCl(g) The initial rate of the reaction is measured at several di

Ira Lisetskai [31]

Answer : The correct rate law for the reaction is,

$\text{Rate}=k[CHCl_3][Cl_2]^{1/2}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$CHCl_3(g)+Cl_2(g)\rightarrow CCl_2(g)+HCl(g)$

Rate law expression for the reaction:

$\text{Rate}=k[CHCl_3]^a[Cl_2]^b$

where,

a = order with respect to $CHCl_3$

b = order with respect to $Cl_2$

Expression for rate law for first observation:

$0.0035=k(0.010)^a(0.010)^b$ ....(1)

Expression for rate law for second observation:

$0.0069=k(0.020)^a(0.010)^b$ ....(2)

Expression for rate law for third observation:

$0.0098=k(0.020)^a(0.020)^b$ ....(3)

Expression for rate law for fourth observation:

$0.027=k(0.040)^a(0.040)^b$ ....(4)

Dividing 1 from 2, we get:

$\frac{0.0069}{0.0035}=\frac{k(0.020)^a(0.010)^b}{k(0.010)^a(0.010)^b}\\\\2=2^a\\a=1$

Dividing 2 from 3, we get:

$\frac{0.0098}{0.0069}=\frac{k(0.020)^a(0.020)^b}{k(0.020)^a(0.010)^b}\\\\1.42=2^b\\b=\frac{1}{2}$

Calculation used :

$1.42=2^b\\\log (1.42)=b\log 2\\\log (\frac{1.42}{2})=b\\b=0.5=\frac{1}{2}$

Thus, the rate law becomes:

$\text{Rate}=k[CHCl_3]^1[Cl_2]^{1/2}$

7 0

3 years ago

(9) Which is true from the following ?

fredd [130]

Answer:

The correct answer is A and D.

Explanation:

Please I want brainliest.

Reason:

The size of the ions follows the order:

Negatively charged ion > Neutral atom >

Positively charged ion

This is because of the size of ions increases when the electrons are added to the outermost shell of an atom.

This happens due to the increase in

electron-electron repulsion.

Moreover, when the electrons are removed from an atom, then the affective nuclear charge that is experienced by the outermost electron increases.

Thus the size of the positively charged ion is least.

4 0

2 years ago

Identify the hybridization of each carbon atom for the molecule above

ipn [44]

Carbons starting from the left end:

sp²
sp²
sp²
sp
sp

Refer to the sketch attached.

<h3>Explanation</h3>

The hybridization of a carbon atom depends on the number of electron domains that it has.

Each chemical bond counts as one single electron domain. This is the case for all chemical bonds: single, double, or triple. Each lone pair also counts as one electron domain. However, lone pairs are seldom seen on carbon atoms.

Each carbon atom has four valence electrons. It can form up to four chemical bonds. As a result, a carbon atom can have up to four electron domains. It has a minimum of two electron domains, with either two double bonds or one single bond and one triple bond.

A carbon atom with four electron domains is sp³ hybridized;
A carbon atom with three electron domains is sp² hybridized;
A carbon atom with two electron domains is sp hybridized.

Starting from the left end (H₂C=CH-) of the molecule:

The first carbon has three electron domains: two C-H single bonds and one C=C double bond; It is sp² hybridized.
The second carbon has three electron domains: one C-H single bond, one C-C single bond, and one C=C double bond; it is sp² hybridized.

The third carbon has three electron domains: two C-C single bonds and one C=O double bond; it is sp² hybridized.
The fourth carbon has two electron domains: one C-C single bond and one C≡C triple bond; it is sp hybridized.
The fifth carbon has two electron domains: one C-H single bond and one C≡C triple bond; it is sp hybridized.