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gregori [183]
3 years ago
13

IF your good at CHEMISTRY plls helpp!!!

Chemistry
1 answer:
gulaghasi [49]3 years ago
6 0

molar concentration of Sn²⁺ ions = 0.273 M

molar concentration of Al³⁺ ions = 0.415 M

molar concentration of Cl⁻ ions = 1.692 M

Explanation:

First we calculate the number of moles of tin (II) chloride (SnCl₂) in the first solution:

number of moles = molar concentration × volume (L)

number of moles of SnCl₂ = 0.55 × 0.45 = 0.248 moles

And the number of moles of aluminum chloride (AlCl₃) in the second solution:

number of moles = molar concentration × volume (L)

number of moles of AlCl₃ = 0.7 × 0.65 = 0.455 moles

0.248 moles of SnCl₂ contains 0.248 moles of Sn²⁺ ions and 2 × 0.248 = 0.496 moles of Cl⁻ ions

0.455 moles of AlCl₃ contains 0.455 moles of Al³⁺ ions and 3 × 0.455 = 1.365 moles of Cl⁻ ions

Volume of the final solution = 450 mL + 650 mL = 1100 mL = 1.1 L

molar concentration = number of moles / volume (L)

molar concentration of Sn²⁺ ions = 0.248 / 1.1 = 0.273 M

molar concentration of Al³⁺ ions = 0.455 / 1.1 = 0.415 M

molar concentration of Cl⁻ ions = (0.496 + 1.365) / 1.1 = 1.692 M

Learn more about:

molar concentration

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Answer:

81.3%

Explanation:

Step 1:

The balanced equation for the reaction:

This is shown below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Step 2:

Data obtained from the question. This includes:

Mass of propane (C3H8) = 470 g

Actual yield of water (H2O) = 625 g

Percentage yield of water (H2O) =?

Step 3:

Determination of the mass of propane (C3H8) burned and the mass of water (H2O) produce from the balanced equation. This is illustrated below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 4 x 18 = 72g

From the balanced equation above,

44g of C3H8 was burned and 72g of H2O was produced.

Step 4:

Determination of the theoretical yield of H2O. This is illustrated below:

From the balanced equation above,

44g of C3H8 produced 72g of H2O.

Therefore, 470g of C3H8 will produce = (470x72)/44 = 769.09g of H2O.

Therefore, the theoretical yield of H2O is 769.09g

Step 5:

Determination of the percentage yield of water (H2O). This is illustrated below:

Actual yield of water (H2O) = 625g

theoretical yield of H2O = 769.09g

Percentage yield of water (H2O) =?

Percentage yield = Actual yield/Theoretical yield x100

Percentage yield = 625/769.09 x100

Percentage yield = 81.3%

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The pH at equivalence point is 12.46

At equivalence point, number of moles of acid, n equals number of moles of base, n'

So, n = n'

CV = C'V' where

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<h3>Concentration of ammonia solution</h3>

Making C' subject of the formula, we have

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Substituting the values of the variables into the equation, we have

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C' = 0.0470 M × 16.0 mL/26.0 mL

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<h3>The concentration of acid at equivalence point</h3>

We know that the ion-product of water Kw is

Kw = [H⁺][OH⁻] =  where

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Making [H⁺] subject of the formula, we have

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[H⁺] = 1.01 × 10⁻¹⁴/0.0289

[H⁺] = 34.95 × 10⁻¹⁴

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<h3>pH at equivalence point</h3>

Since pH = -㏒[H⁺]

pH = -㏒[3.495 × 10⁻¹³]

pH = -㏒[3.495] + (-㏒10⁻¹³)

pH = -㏒[3.495] + [-13(-㏒10)]

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So, the pH at equivalence point is 12.46

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