How many moles are in a 63.60 g sample of carbon? (the molar mass of carbon is 12.01 g/mol.)
2 answers:
Answer:
5.29 moles
Explanation:
In order to calculate this you just have to divide the grams of the element that there are by the grams of that given atom that make uo for a mol, in this case for carbon 12.01 grams make up a mol, so we just have to divide the gram that we have by 12.01 grams:
So we know that there are 5.29 moles in 63.6 grams of carbon.
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Answer:
mole fraction of C6H6 = 0.613 atm
Explanation:
The equation for this reaction is :
Initial P₁ P₂ 0
Final 0 P₂ -P₁/2 P₁
After completion of the reaction;
P₁ + P₂ = 1.21 atm ----- (1)
P₂ - P₁/2 + P₁ = 0.839 atm
P₂ + P₁/2 = 0.839 atm ----- (2)
Subtracting (2) from (1); we have:
P₁/2 = 0.371
P₁ = 0.742 atm
From(1)
P₁ + P₂ = 1.21 atm
0.742 atm + P₂ = 1.21 atm
P₂ = 1.21 atm - 0.742 atm
P₂ = 0.468 atm
Thus, the partial pressure of C6H6 = 0.742 atm
∴
Partial pressure = Total pressure × mole fraction of C6H6
mole fraction of C6H6 = Partial pressure / Total pressure
mole fraction of C6H6 = 0.742 atm / 1.21 atm
mole fraction of C6H6 = 0.613 atm