How many moles are in a 63.60 g sample of carbon? (the molar mass of carbon is 12.01 g/mol.)
2 answers:
Answer:
5.29 moles
Explanation:
In order to calculate this you just have to divide the grams of the element that there are by the grams of that given atom that make uo for a mol, in this case for carbon 12.01 grams make up a mol, so we just have to divide the gram that we have by 12.01 grams:
So we know that there are 5.29 moles in 63.6 grams of carbon.
You might be interested in
Taking into account the reaction stoichiometry, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
2 Bi + 3 Cl₂ → 2 BiCl₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Bi: 2 moles
- Cl₂: 3 moles
- BiCl₃: 2 moles
The molar mass of the compounds is:
- Bi: 209 g/mole
- Cl₂: 70.90 g/mole
- BiCl₃: 315.45 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Bi: 2 moles ×209 g/mole=418 g
Cl₂: 3 moles ×70.90 g/mole= 212.7 g
BiCl₃: 2 moles ×315.45 g/mole= 630.9 g
<h3>Mass of Cl₂ required</h3>The following rule of three can be applied: If by reaction stoichiometry 630.9 grams of BiCl₃ are formed by 212.7 grams of Cl₂, 3.32 grams of BiCl₃ are formed by how much mass of Cl₂?
<u><em>mass of Cl₂= 1.119 grams</em></u>
Finally, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.
Learn more about the reaction stoichiometry: