The reducing agent can approach the carbonyl face of camphor by forming a one carbon bridge (known as an exo attack) or a two carbon bridge (termed endo).
The two resultant stereoisomers are known as isoborneol and borneol (from exo attack) (from endo attack). Gas chromatography (GC) analysis may be used to calculate the ratio of each isomeric alcohol in the mixture. Unfortunately, IR analysis does not permit this.
The stereochemistry of the reaction is regulated in stiff cyclic compounds like camphor and norcamphor by protecting one side of the carbonyl group from the reagent's assault. The hydrogen atom is added to the endo side, creating the exo alcohol isoborneol, while the methyl groups on the one-carbon bridge of camphor screen the approach of the hydride from the "top" or exo side of the two-carbon bridge. You will be asked to guess the main isomeric alcohol created by the norcamphor hydride reduction later in the lab report.
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Answer:
there are 4 hydrogen so
A.the mass of Hydrogen in the reactant side of the equation above is 1×4=4 amu.
B.the mass of Hydrogen on the product side of the equation above =1×4=4 amu.
<u>Note</u><u>:</u><u> </u><u>mass</u><u> </u><u>of</u><u> </u><u>reactant</u><u> </u><u>=</u><u>mass</u><u> </u><u>of</u><u> </u><u>product</u><u>.</u>
It will sink because it is heavier than the water.
Answer:
The reaction rate or rate of reaction is the speed at which a chemical reaction takes place, defined as proportional to the increase in the concentration of a product per unit time and to the decrease in the concentration of a reactant per unit time. Reaction rates can vary dramatically.
Through looking at the graph, i feel that its the number of the temperature.