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Fynjy0 [20]
4 years ago
8

Assuming one nerve impulse must end before another can begin, what is the maximum firing rate of a nerve in impulses per second?

Assume that it takes a millisecond for an impulse to travel through a nerve cell.
Physics
1 answer:
Len [333]4 years ago
7 0

Answer:

1000/second

Explanation:

A nerve impulse is rise or fall of membrane potential in a certain region of a cell.

One nerve impulse lasts for 1 ms which is 10⁻³ seconds.

In the question it is given that one nerve impulse begins after one nerve impulse ends.

In 1 second there are 1000 ms.

So, the neuron firing rate would be 1000/second. This means that a nerve impulse will fire a thousand times each second.

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A guitar string with a linear density of 2.0 g/m is stretched between supports that are 60 cm apart. The string is observed to f
Butoxors [25]

<h2>The frequency of driver is 700 Hz</h2>

Explanation:

The frequency of wave in a string is given by the relation

n = \frac{p}{2l} \sqrt{\frac{T}{m} }

here n is the frequency

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T is the tension in string and m is the mass per unit length

Thus 420 =\frac{3}{120} \sqrt{\frac{T}{2} }            I

Now if there is 5 antinodes , the value of p = 5

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3 0
3 years ago
A dish with a mass of 0.4 kg has a force of kinetic friction of 0.15 N exerted on it by moving a tablecloth for a time of 0.2 s.
Hatshy [7]

Answer:

the dish's acceleration is 0.375 m/s^2.

Explanation:

Recall the formula from Newton's 2nd Law:

Force = mass x acceleration.

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