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fenix001 [56]
4 years ago
6

A 2.0 kg tumor is being irradiated by a radioactive source.The

Physics
1 answer:
navik [9.2K]4 years ago
6 0

Answer:

426136363636.36365 Bq

Explanation:

Grays = 12

Mass = 2 kg

Time = 880

Energy = 0.4 MeV

Activity is given by

Activity=\dfrac{Grays\times Mass}{Time\times 0.4}\\\Rightarrow Activity=\dfrac{12\times 2}{880\times 0.4\times 1.6\times 10^{-13}}\\\Rightarrow Activity=426136363636.36365\ Bq

The activity N//t of the radioactive source is 426136363636.36365 Bq

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