Answer:
The hawk reaches the rabbit at t=4.3 sec
Step-by-step explanation:
Let
h ----> is the height in feet
t ----> is the time in seconds
v ---> the initial velocity in feet pr second
s ----- is the starting height
we have
![h=-16t^{2} +vt+s](https://tex.z-dn.net/?f=h%3D-16t%5E%7B2%7D%20%2Bvt%2Bs)
when the hawk reaches the rabbit the value of h is equal to zero
we have
![v=55\ ft/sec](https://tex.z-dn.net/?f=v%3D55%5C%20ft%2Fsec)
![s=60\ ft](https://tex.z-dn.net/?f=s%3D60%5C%20ft)
substitute
![0=-16t^{2} +55t+60](https://tex.z-dn.net/?f=0%3D-16t%5E%7B2%7D%20%2B55t%2B60)
Solve the quadratic equation by graphing
The solution is t=4.3 sec
see the attached figure
I don’t see a picture or anything? Can you explain more I don’t know the sides
Answer is B, -6 - -6 = 0 7-3=4 0/4 =0
A’s slope has no meaning
C’s slope is 1
D’s slope is -14/-18
Answer:22/250
Step-by-step explanation:(google)