The length of a rectangle is 7cm longer than its width. Find the dimensions of the rectangle that make the area of the rectangle
1 answer:
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Let the equal sides of the isosceles Δ ABC be x.
Given that the perimeter of Δ ABC = 50m.
Therefore, 2x + AC = 50 --- (1)
It is also given that the perimeter of Δ ABD = 40m.
Therefore, x + BD + AD = 40
BD is the median of the Δ ABC. Therefore, D is the midpoint of AC.
So AD = CD.
Or, AD = AC
Therefore,
Multiply both sides by 2.
2x + 2BD + AC = 80
From (1), 2x + AC = 50.
Therefore, 2BD + 50 = 80
2BD = 80 - 50
2BD = 30
BD = 15m.
Answer:
Part a) Exactly values
The width of the rectangle is
The length of the rectangle is
Part b) Approximately values
The width of the rectangle is
The length of the rectangle is
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of rectangle is equal to
we have
substitute the values in the formula
so
Solve for x
Divide by 4 both sides
square root both sides
The solution is the positive value
therefore
<em>Exactly values</em>
<em>Approximately values</em>
