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Anuta_ua [19.1K]
3 years ago
14

What is the value of x in 7x-2+x+x

Mathematics
1 answer:
ratelena [41]3 years ago
4 0
Hello,

Work:

Equation;

7x - 2 + x + x

Collect like terms.

9x - 2 \: \: \: \: \: \: \: result

Hope this helps.
r3t40
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Only once, any number higher will pass it
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Write the next three terms of the arithmetic sequence.
konstantin123 [22]

Answer:

t2=15

t3=28

t4=41

first term (a)=2

common difference (d)=13

General terms tn=a+(n-1)d

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Need need need need help help help help help help help help help
GenaCL600 [577]
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The revenue from selling x shirts is r(x)=12x.
kenny6666 [7]

Answer:

p(x) = 7x - 20

Step-by-step explanation:

A company makes a profit selling goods when the revenue taken in from the sales is greater than the cost of those goods:  p(x) = r(x) - c(x) > 0.

In this case the revenue function is r(x) = 12x; the cost function is c(x) = 5x + 20, and the profit function is p(x) = 12x - (5x + 20), or:

p(x) = 12x - 5x - 20, or

p(x) = 7x - 20

4 0
3 years ago
The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.
Dovator [93]

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

Learn more about Domain here -

brainly.com/question/2264373

#SPJ10

3 0
1 year ago
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