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Mrrafil [7]
3 years ago
13

A kno3 solution containing 51 g of kno3 per 100.0 g of water is cooled from 40 ∘c to 0 ∘c. what will happen during cooling?

Chemistry
1 answer:
Gre4nikov [31]3 years ago
5 0

Answer:

As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.

Explanation:

  • Firstly, we must mention that:

The solubility of KNO₃ per 100.0 g of water at 40.0 °C = 63.0 g.

The solubility of KNO₃ per 100.0 g of water at 0.0 °C = 14.0 g.

  • So, at 40.0 °C, 51.0 g of KNO₃ will be completely dissolved in water.
  • <em>As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.</em>
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Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

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\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

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