Explanation:
1. Circumference is pi times diameter.
C = πd
C = 9π inches
C ≈ 28.3 inches
2. Mechanical advantage is ratio of output force to input force.
MA = Fout / Fin
MA = 155 lb / 15 lb
MA ≈ 10.3
3. Mechanical advantage is ratio of input distance over output distance.
MA = din / dout
MA = 10.5 in / 0.85 in
MA ≈ 12.4
4. Mechanical advantage of pulley system is the number of strands.
MA = 8
5. Mechanical advantage is ratio of output force to input force.
MA = Fout / Fin
8 = Fout / 200 lb
Fout = 1600 lb
Answer:
The surface temperature of the ground is = 296.946K
Explanation:
Solution
Given
r₁= 0.05m
r₂= 0.08m
Tn =Ti = 77K
Ki = 0.0035 Wm-1K-1
Kg = 1 Wm-1K-1
Z= 2m
Now,
The outer type temperature (Skin temperature pipe)
Q = T₀ -T₁/ln (r2/r1)/2πKi = 2πKi T0 -T1/ln (r2/r1)
Thus,
10 w/m = 2π * 0.0035 = T0 -77/ln 0.08/0.05
⇒ T₀ -77 = 231.72
T₀= 290.72K
The shape factor between the cylinder and he ground
S = 2πL/ln 4z/D
where L = length of pipe
D = outer layer of pipe
S = 2π * 1/4 *2/ 2 * 0.08 = 1.606m
The heat gained in the pipe is = S * Kg * (Tg- T₀)
(10* 1) = 1.606 * 1* (Tg- 290.72)
Tg - 290.72 = 6.2266
Tg = 296.946K
Therefore the surface temperature to the ground is 296.946K
A) The Camshaft Controls The Opening of The Engines Valves
Answer: The first nationwide US light duty vehicle emission standards were implemented in 1968, and subsequently reviewed every couple of years. New standards were referred to by the effective model year of the regulation from 1968 to 1987
I have attached an image showing the shear stresses and direction.
Answer:
Resolved shear stress = 5.6MPa
Explanation:
From the diagram attached,
Cos λ = [(0,-1,1)•(0,0,1)]/[(√(0^2 + (-1)^2 + 1^2)) + (√(0^2 + 0^2 + 1^2))]
= 1/(√2 x√1) = 1/√2
Also, Cos Φ = [(1,1,1)•(0,0,1)]/[(√(1^2 + 1^2 + 1^2)) + (√(0^2 + 0^2 + 1^2))]
= 1/(√3 x√1) = 1/√3
So resolved shear stress (τ resolved) = 13.7 x (1/√2) x (1/√3) = 13.7 x (1/√6) = 5.593 or approximately 5.6MPa
