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Ne4ueva [31]
1 year ago
10

the left rear brake drum is scored, but the right rear drum looks as good as new. technician a says the left-side drum should be

resurfaced and the right-side drum should be reinstalled without resurfacing. technician b says both sides should be remachined to a similar diameter. who is correct?
Engineering
1 answer:
Romashka-Z-Leto [24]1 year ago
7 0

Technician b is correct because the left rear brake drum is scored, but the right rear drum looks as good as new then both sides should be remachined to a similar diameter.

A brake drum is a revolving cylinder-shaped component that is friction-activated by a set of shoes or pads pressing outward against it. Drum brakes are brakes where shoes are pressed against the inner surface of the drum. Drum brakes are frequently used at the rear. Compared to disc brakes, these brakes have more parts and are more difficult to maintain, but they cost less to make and are simple to add an emergency braking mechanism. The front and rear brakes are standard equipment on all automobiles. Your car may have a "disc brake" system on all four wheels, a "drum brake" system on all four wheels, or a combination of the two. Typically, the front brakes of your car have a disc system, and the rear brakes have a drum system.

Learn more about brake drum here:

brainly.com/question/14937026

#SPJ4

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Write a function which multiplies the values in odd position values by 10. Odd positions in this case refers to the first value
xxMikexx [17]

Answer:

Using linkedlist on C++, we have the program below.

Explanation:

#include<iostream>

#include<cstdlib>

using namespace std;

//structure of linked list

struct linkedList

{

  int data;

  struct linkedList *next;

};

//print linked list

void printList(struct linkedList *head)

{

  linkedList *t=head;

 

  while(t!=NULL)

  {

      cout<<t->data;

      if(t->next!=NULL)

      cout<<" -> ";

     

      t=t->next;

  }

}

//insert newnode at head of linked List

struct linkedList* insert(struct linkedList *head,int data)

{

  linkedList *newnode=new linkedList;

  newnode->data=data;

  newnode->next=NULL;

 

  if(head==NULL)

  head=newnode;

  else

  {

      struct linkedList *temp=head;

      while(temp->next!=NULL)

      temp=temp->next;

     

      temp->next=newnode;

     

      }

  return head;

}

void multiplyOddPosition(struct linkedList *head)

{

  struct linkedList *temp=head;

  while(temp!=NULL)

  {

      temp->data = temp->data*10; //multiply values at odd position by 10

      temp = temp->next;

      //skip odd position values

      if(temp!= NULL)

      temp = temp->next;

  }

}

int main()

{

  int n,data;

  linkedList *head=NULL;

 

// create linked list

  head=insert(head,20);

  head=insert(head,5);

  head=insert(head,11);

  head=insert(head,17);

  head=insert(head,23);

  head=insert(head,12);

  head=insert(head,4);

  head=insert(head,21);    

 

  cout<<"\nLinked List : ";

  printList(head); //print list

 

  multiplyOddPosition(head);

  cout<<"\nLinked List After Multiply by 10 at odd position : ";

  printList(head); //print list

 

  return 0;

}

5 0
3 years ago
Rod of steel, 200 mm length reduces its diameter (50 mm) by turning by 2 mm with feed speed 25 mm/min. You are required to calcu
diamong [38]

Answer:

125 cm³/min

Explanation:

The material rate of removal is usually given by the formula

Material Rate of Removal = Radial Depth of Cut * Axial Depth of Cut * Feed Rate, where

Radial Depth of Cut = 25 mm

Axial depth of cut = 200 mm

Feed rate = 25 mm/min

On multiplying all together, we will then have

MRR = 25 mm * 200 mm * 25 mm/min

MRR = 125000 mm³/min

Or we convert it to cm³/min and have

MRR = 125000 mm³/min ÷ 1000

MRR = 125 cm³/min

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Answer:

32 horsepower will be equal to 17600 ft-lb/sec

Explanation:

We have given 1 horsepower = 550 ft-lb/sec

We have to convert 32 horsepower into ft-lb/sec

As we know that 1 horsepower is equal to 550 ft-lb/sec

So for converting horsepower to ft-lb/sec we have multiply with 550

We have given 32 horse power

So 32\ horsepower =32\times 550=17600ft-lb/sec

So 32 horsepower will be equal to 17600 ft-lb/sec

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