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Ne4ueva [31]
1 year ago
10

the left rear brake drum is scored, but the right rear drum looks as good as new. technician a says the left-side drum should be

resurfaced and the right-side drum should be reinstalled without resurfacing. technician b says both sides should be remachined to a similar diameter. who is correct?
Engineering
1 answer:
Romashka-Z-Leto [24]1 year ago
7 0

Technician b is correct because the left rear brake drum is scored, but the right rear drum looks as good as new then both sides should be remachined to a similar diameter.

A brake drum is a revolving cylinder-shaped component that is friction-activated by a set of shoes or pads pressing outward against it. Drum brakes are brakes where shoes are pressed against the inner surface of the drum. Drum brakes are frequently used at the rear. Compared to disc brakes, these brakes have more parts and are more difficult to maintain, but they cost less to make and are simple to add an emergency braking mechanism. The front and rear brakes are standard equipment on all automobiles. Your car may have a "disc brake" system on all four wheels, a "drum brake" system on all four wheels, or a combination of the two. Typically, the front brakes of your car have a disc system, and the rear brakes have a drum system.

Learn more about brake drum here:

brainly.com/question/14937026

#SPJ4

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Compare both xbox and playstaion. What are pros and cons between the two gaming systems. What is your game system of choice?
fredd [130]
Neither, I would choose a PC because normally with PlayStation and Xbox you have to go to the store to buy more games when on a PC there are some games for free
7 0
2 years ago
Un mol de gas ideal realiza un trabajo de 3000 J sobre su entorno, cuando se expande de manera isotermica a una temperatura de 5
Shkiper50 [21]

Answer:

74,4 litros

Explanation:

Dado que

W = nRT ln (Vf / Vi)

W = 3000J

R = 8,314 JK-1mol-1

T = 58 + 273 = 331 K

Vf = desconocido

Vi = 25 L

W / nRT = ln (Vf / Vi)

W / nRT = 2.303 log (Vf / Vi)

W / nRT * 1 / 2.303 = log (Vf / Vi)

Vf / Vi = Antilog (W / nRT * 1 / 2.303)

Vf = Antilog (W / nRT * 1 / 2.303) * Vi

Vf = Antilog (3000/1 * 8,314 * 331 * 1 / 2,303) * 25

Vf = 74,4 litros

3 0
3 years ago
Thermal energy is...
Yuki888 [10]
B because thermal has to do with temperature and it’s the amount of kinetic and potential energy in and object
4 0
2 years ago
Read 2 more answers
Steam enters an adiabatic turbine operating at steady state at 2MPa, 400 C with velocity of 50 m/s and exit at 15 KPasquality of
goldenfox [79]

Answer:

P=4833.45 KW

Explanation:

At inlet:

Properties of steam at 2 MPa and 400°C

h_1=3248.22\frac{KJ}{Kg}

V_1=50 m/s

At exit:

Properties of steam at 15 KPa

We know that if we know only one property in side the dome then we will find the other property by using steam property table.

So at 15 KPa

h_f= 33.61\frac{KJ}{Kg} ,h_g=2515.2\frac{KJ}{Kg}

V_2=180m/s

h_2=h_f+x(h_g-h_f)\frac{KJ}{Kg}

h_2=33.61+0.9(2515.2-33.61)\frac{KJ}{Kg}  h_2=2267.04\frac{KJ}{Kg}

Now from first law of thermodynamics for open system

h_1+\dfrac{V_1^2}{2}+Z_1g+Q=h_2+\dfrac{V_2^2}{2}+Z_2g+w

Z_1=47 m,Z_2=0

Here given that turbine is adiabatic so Q=0

Now put the all values

3248.22+\dfrac{50^2}{2000}+47\times 9.81\times 10^{-3}+0=2267.04+\dfrac{180^2}{2000}+W

W=966.69\frac{KJ}{Kg}

So power developed P=m\times W

 P=5\times966.69                                            

P=4833.45 KW

5 0
3 years ago
You will write a function that determines if a password is "strong" or "weak". Your function willhave one parameter, the passwor
madreJ [45]

Answer:

def checkStrength(password):

   lower = False

   upper = False

   digit = False

   length = False

   characters = False

   chars = ["@", "*", "&", "$", "!"]

   if len(password) < 8:

       length = False

   else:

       length = True

   for c in password:

       if c.isdigit():

           digit = True

       if c.islower():

           lower = True

       if c.isupper():

           upper = True

       if c in chars:

           characters = True

   if lower and upper and digit and length and characters:

       return "Strong"

   else:

       return "Weak"

print(checkStrength("[email protected]"))

end

7 0
3 years ago
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