Answer: 1725
Step-by-step explanation: A= A+B/2 h= 50+65/2x30=1725
First we need the area of the whole shape (A=l*w)
A:A=7*5 or 35 (7 because you add 3 and 4)
B:A=3*4 or 12
C:A=4*4 or 16
D:A=3*9 or 27 (9 because you add 5 and 4)
So the whole area is 35+12+16+27 = 90
Then we do the part divided by the whole to find probability
=27/90 which can be simplified to 3/10
Hope this helps
It’ll be divided by -1/2 for each number
Answer:
2b+0.75c = $34
Step-by-step explanation:
the letter b represents the amount of brownies and the letter c represents the number of cookies. each variable is accompanied by the price of that item. the 34 at the end of the equation represents the total cost for all of the items.
Answer:
8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)
9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.
10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)
Step-by-step explanation:
For a couple of these, it is helpful to remember that (a-b) = -(b-a).
<h3>8d.</h3>
![\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7Bx%2B2%7D%2B%5Cdfrac%7B25-x%7D%7Bx%5E2-3x-10%7D%3D%5Cdfrac%7B5%28x-5%29%7D%7B%28x%2B2%29%28x-5%29%7D%2B%5Cdfrac%7B25-x%7D%7B%28x%2B2%29%28x-5%29%7D%5C%5C%5C%5C%3D%5Cdfrac%7B5x-25%2B25-x%7D%7B%28x%2B2%29%28x-5%29%7D%3D%5Cdfrac%7B4x%7D%7Bx%5E2-3x-10%7D)
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<h3>9b.</h3>
![\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B%5Cleft%28%5Cfrac%7Bx%7D%7Bx-2%7D%5Cright%29%7D%7B%5Cleft%28%5Cfrac%7B2x%7D%7B2-x%7D%5Cright%29%7D%3D%5Cfrac%7Bx%7D%7Bx-2%7D%5Ccdot%5Cfrac%7B-%28x-2%29%7D%7B2x%7D%3D%5Cfrac%7B-x%28x-2%29%7D%7B2x%28x-2%29%7D%3D-%5Cfrac%7B1%7D%7B2%7D)
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<h3>10b.</h3>
![\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7Bx-1%7D%2B%5Cdfrac%7B6%7D%7Bx%5E2-3x%2B2%7D%3D2%5C%5C%5C%5C%5Cdfrac%7B3%28x-2%29%7D%7B%28x-1%29%28x-2%29%7D%2B%5Cdfrac%7B6%7D%7B%28x-1%29%28x-2%29%7D%3D%5Cdfrac%7B2%28x-1%29%28x-2%29%7D%7B%28x-1%29%28x-2%29%7D%5C%5C%5C%5C3x-6%2B6%3D2%28x%5E2-3x%2B2%29%20%5Cqquad%5Ctext%7Bmultiply%20by%20the%20denominator%7D%5C%5C%5C%5C2x%5E2-9x%2B4%3D0%20%5Cqquad%5Ctext%7Bsubtract%203x%7D%5C%5C%5C%5C%282x-1%29%28x-4%29%3D0%20%5Cqquad%5Ctext%7Bfactor%3B%20x%3D1%2F2%2C%20x%3D4%7D)
Neither solution makes any denominator be zero, so both are good solutions.