All categories

3 years ago

Light energy, 6H2O, and 6CO2 are at the start of photosynthesis. True or False

Chemistry

2 answers:

IrinaVladis [17]3 years ago

4 0

The answer to this question is true

Kay [80]3 years ago

3 0

The best answer between the two choices would be the first option TRUE because light energy, 6H2O, & 6CO2 ARE at the start of photosynthesis.

You might be interested in

Suggest a way of improving

bezimeni [28]

Explanation:

when water is boiling and when u cover it and increase the pressure it causes the increase in rate of condensation.

4 0

3 years ago

Why is it important to keep the two sides of an equation balanced when solving? what other properties do we use to rewrite expre

kompoz [17]

Answer:

Why is it important to keep the two sides of an equation balanced when solving?

If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal. When you solve an equation, you find the value of the variable that makes the equation true.

What other properties do we use to rewrite expressions and equations?

State of matter

Please vote for Brainliest and I hope this helps!

4 0

2 years ago

mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of

anygoal [31]

Answer: The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

Explanation:

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

$1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol$

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

For nitrogen gas:

Molar mass of nitrogen gas = 28 g/mol

$\text{Moles of nitrogen gas}=\frac{x}{28}mol$

For hydrogen gas:

Molar mass of hydrogen gas = 2 g/mol

$\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol$

Equating the moles of the individual gases to the moles of mixture:

$0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g$

To calculate the mass percentage of substance in mixture we use the equation:

$\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100$

Mass of the mixture = 13.22 g

For nitrogen gas:

Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

$\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%$

For hydrogen gas:

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

$\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%$

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

5 0

3 years ago

Use what you know about relative dating to choose the correct answers from the drop-down menus. Ethan determines that layer B is

AURORKA [14]

Answer: yes

Explanation: no

5 0

3 years ago

Read 2 more answers

Help pls! Answer all of it. Idk if what I wrote is correct.

trasher [3.6K]

The reaction is actually endothermic because delta H is positive, indicating that it absorbing heat.

8 0

3 years ago