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hoa [83]
3 years ago
7

At physiological ph, the ionized state of the carboxyl (cooh) group in the r group of aspartic acid is:

Chemistry
1 answer:
Wewaii [24]3 years ago
3 0
Answer is: the ionized state of the carboxyl group is COO⁻.
Physiological pH is 7,4 and carboxyl group in the R group has pKa = 3,7. Since this pKa is lower than phys<span>iological pH of 7,4, carboxyl group (COOH) will lost proton, and because of that it will be deprotonated and will have negative charge.
</span>Aspartic acid<span> is an α-amino acid that is used in the biosynthesis of proteins.</span>
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Answer:-  \Delta H_s_o_l_n=-37.2\frac{kJ}{mol}

Solution:- First of all we calculate the heat absorbed or released when the solute is added to the solvent. Here the solute is LiCl and the solvent is water.

To calculate the heat absorbed or released we use the formula:

q=ms\Delta T

q = heat absorbed or released

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s = specific heat capacity

and \Delta T = change in temperature

mass of solution = mass of solute + mass of solvent

mass of solution = 5.00 g + 100.0 g = 105.0 g

(note:- density of pure water is 1 g per mL so the mass is same as its volume)

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Let's plug in the values in the formula and calculate q.

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q = 4389 J

To calculate the enthalpy of solution that is \Delta H_s_o_l_n we convert q to kJ and divide by the moles of solute.

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= 0.118 moles

q = 4389J(\frac{1kJ}{1000J}) = 4.389 kJ

\Delta H_s_o_l_n=\frac{4.389kJ}{0.118mol}

\Delta H_s_o_l_n = 37.2\frac{kJ}{mol}

Since the heat is released which is also clear from the rise in temperature of the solution, the sign of enthapy of solution will be negative.

So,  \Delta H_s_o_l_n=-37.2\frac{kJ}{mol}


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Which is compound formed from a metal cation and nonmetal anion?
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All the other options have two non metals
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