Hey there!:
Balanced equation:
F2(g) + CaBr2(s) ---> CaF2 + Br2
1 mol F2 = 1 mol CaBr2
Calculation:
2.31 g CaBr2
* (1 mol CaBr2 / 199.886 g CaBr2) * (1 mol F2 / 1 mol CaBr2)
= 0.0115565 moles of F2:
Assuming F2 is an ideal
gas at these conditions:
P*V = n*R*T
Solving for V:
V = (n *R* T) / P
where :
n = 0.0115565 moles
R = 0.08206 atm·L/mol·K
Temperature in K = 35 + 273.15 => 308.15 K
P = 8.19 atm
Substituting numbers into V = (n x R x T) / P:
V = 0.0115565 * 0.08206 * 308.15 / 8.19
V = 0.29222 / 8.19
V = 0.0357 or 3.57*10⁻² L
You are correct!!!
Hope that helps!
Considering a reaction:
A → B
The rate equation may be described as:
r = -k[A]ⁿ
Taking the natural log,
ln(r) = -nln([A]) + ln(k)
Therefore, the only time the graph of ln[A] vs time will be a straight line is when the order of the reaction is 0, meaning the reaction is independent of reactant concentration.
First, let's state the chemical reaction:

We can find the number of moles of Cl2 required to produce 0.0923 moles of AlCl3, doing a rule of three: 3 moles of Cl2 reacted produces 2 moles of AlCl3:

The calculation would be:

And the final step is to convert this number of moles to grams. Remember that the molar mass can be calculated using the periodic table, so the molar mass of Cl2 is 70.8 g/mol, and the conversion is:

The answer is that we need 9.770 grams of Cl2 to produce 0.0923 moles of AlCl3.
Answer:
this is answers to the second picture
Explanation:
1- energy
2- structure
3- reaction
4- substance
5- reactants
6- products
7- changed
8- At first there is no reaction because of the protective oxide coating on the aluminum. But soon an exothermic reaction between bromine and aluminum causes brown fumes of bromine to be given off. But as a new substance, aluminum bromide is produced. White smoke is produced.
9- heated to 120 degrees Celsius it melts and first forms a pale-yellow liquid.
In this form the atoms are covalently bonded, and the liquid can flow easily. However, heated up beyond 150 degrees Celsius, the result is a dark red
10- When a chemical change occurs it is more difficult to revert the substance back to its original state. (To be honest I don't know)
<span>The energy (E) per photon is expressed by Planck's equation: E = hf, where f is
the frequency and h is Planck's constant, experimentally determined to be
6.625 * 10**-34 joule-seconds. So to find E, we multiply h by the frequency
and obtain E = hf = (6.625 * 10**-34)(7.0 * 10**14) = 46.375 * 10**-20 joule
or in standard notation, E = 4.6375 * 10**-19 joule per photon.
Hope this answers your question.Sorry if I calculated wrong.</span>