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scZoUnD [109]
2 years ago
12

Consider the reaction:

Chemistry
1 answer:
kramer2 years ago
3 0

Answer:

SOMEONE ANSWER THIS PLEASE

Explanation:

PLEASE

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what volume (L) of fluorine gas is required to react with 2.31 g of calcium bromide to form calcium fluoride and bromine gas at
MrRa [10]

Hey there!:

Balanced equation:

F2(g) + CaBr2(s) ---> CaF2 + Br2

1 mol F2 = 1 mol CaBr2

Calculation:

2.31 g CaBr2 * (1 mol CaBr2 / 199.886 g CaBr2)  * (1 mol F2 / 1 mol CaBr2)

= 0.0115565 moles of F2:

Assuming F2 is an ideal  

gas at these conditions:

P*V = n*R*T

Solving for V:

V = (n *R* T) / P

where :

n = 0.0115565 moles

R = 0.08206 atm·L/mol·K

Temperature in K = 35 + 273.15 => 308.15 K

P = 8.19 atm

Substituting numbers into V = (n x R x T) / P:

V = 0.0115565 * 0.08206 * 308.15 / 8.19

V = 0.29222 / 8.19

V = 0.0357 or 3.57*10⁻² L

You are correct!!!


Hope that helps!

5 0
2 years ago
When might a plot of ln[a] vs time not yield a straight line?
podryga [215]
Considering a reaction:
A → B
The rate equation may be described as:
r = -k[A]ⁿ
Taking the natural log,
ln(r) = -nln([A]) + ln(k)
Therefore, the only time the graph of ln[A] vs time will be a straight line is when the order of the reaction is 0, meaning the reaction is independent of reactant concentration.
6 0
3 years ago
How many grams of Cl2 must react to produce 0.0923 mol of AlCl3? Show work.
alexandr402 [8]

First, let's state the chemical reaction:

2Al+3Cl_2\to2AlCl_3\text{.}

We can find the number of moles of Cl2 required to produce 0.0923 moles of AlCl3, doing a rule of three: 3 moles of Cl2 reacted produces 2 moles of AlCl3:

\begin{gathered} 3molesCl_2\to2molesAlCl_3 \\ \text{?moles Cl}_2\to0.0923\text{ moles }AlCl_3\text{.} \end{gathered}

The calculation would be:

0.0923molesAlCl_3\cdot\frac{3molesCl_2}{2molesAlCl_3}=0.138molesCl_2.

And the final step is to convert this number of moles to grams. Remember that the molar mass can be calculated using the periodic table, so the molar mass of Cl2 is 70.8 g/mol, and the conversion is:

0.138molesCl_2\cdot\frac{70.8gCl_2}{1molCl_2}=9.770gCl_2.

The answer is that we need 9.770 grams of Cl2 to produce 0.0923 moles of AlCl3.

3 0
8 months ago
Help me pls
harkovskaia [24]

Answer:

this is answers to the second picture

Explanation:

1-   energy

2- structure

3- reaction

4- substance

5- reactants

6- products

7- changed

8- At first there is no reaction because of the protective oxide coating on the aluminum. But soon an exothermic reaction between bromine and aluminum causes brown fumes of bromine to be given off. But as a new substance, aluminum bromide is produced. White smoke is produced.

9-   heated to 120 degrees Celsius it melts and first forms a pale-yellow liquid.

In this form the atoms are covalently bonded, and the liquid can flow easily. However, heated up beyond 150 degrees Celsius, the result is a dark red

10- When a chemical change occurs it is more difficult to revert the substance back to its original state. (To be honest I don't know)

3 0
2 years ago
A certain shade of blue has a frequency of 7.02 × 1014 Hz. What is the energy of exactly one photon of this light?
ruslelena [56]
 <span>The energy (E) per photon is expressed by Planck's equation: E = hf, where f is 
the frequency and h is Planck's constant, experimentally determined to be 
6.625 * 10**-34 joule-seconds. So to find E, we multiply h by the frequency 
and obtain E = hf = (6.625 * 10**-34)(7.0 * 10**14) = 46.375 * 10**-20 joule 
or in standard notation, E = 4.6375 * 10**-19 joule per photon. 

Hope this answers your question.Sorry if I calculated wrong.</span>
4 0
2 years ago
Read 2 more answers
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