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Marina CMI [18]
4 years ago
5

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Mathematics
1 answer:
shusha [124]4 years ago
4 0
For question 1, just plug in -2 as <em>h.

</em>-2(-2)^2-(-2)+2
<em>
</em>You would get...

h(-2)=-4
<em>
</em>Hope this helped! <em>-4, or option 1, is correct!</em><em>
</em>
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Answer:

The solution of the given set in interval form is $(-\infty,-4] \cup[12, \infty)$.

Step-by-step explanation:

It is given in the question an inequality as $|x-4| \geq 8$.

It is required to determine the solution of the inequality.

To determine the solution of the inequality, solve the inequality $x-4 \geq 8$ and, $x-4 \leq-8$

Step 1 of 2

Solve the inequality $x-4 \geq 8$

$$\begin{aligned}&x-4 \geq 8 \\&x-4+4 \geq 8+4 \\&x \geq 12\end{aligned}$$

Solve the inequality $x-4 \leq-8$.

$$\begin{aligned}&x-4 \leq-8 \\&x-4+4 \leq-8+4 \\&x \leq-4\end{aligned}$$

Step 2 of 2

The common solution from the above two solutions is x less than -4 and $x \geq 12$.

The solution set in terms of interval is $(-\infty,-4] \cup[12, \infty)$.

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