Question

Suppose P(E) = 81%; P(E and F) = 9%; and P(E or F) = 65%,

Answer 1

Using Venn probabilities, it is found that P(F) = -0.07, which is not a probability, as it is a negative value.

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• We have two events, E and F.
• Their probabilities are: $P(E) = 0.81, P(E \cap F) = 0.09, P(E \cup F) = 0.65$
• The probabilities are related by the following equation:

$P(E \cap F) = P(E) + P(F) - P(E \cup F)$

• Replacing into the equation, we can find P(F).

$0.09 = 0.81 + P(F) - 0.65$

$0.16 + P(F) = 0.09$

$P(F) = -0.07$

P(F) = -0.07, which is not a probability, as it is a negative value.

A similar problem is given at brainly.com/question/21421475