I believe the correct answer is D. All of the above.
The probability of the offspring of a heterozygous father and homzygous mother having five fingers is 50%.
<h3>How to calculate genotype of a cross?</h3>
According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.
If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:
This shows that the probability of the offspring of a heterozygous father and homzygous mother having five fingers is ½ (50%).
Learn more about genotype at: brainly.com/question/12116830
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<em>Although the landscape shows a certain ability to persist, underground mining activity has caused some effects such as ground fissures (cracking), disturbance of the vegetation community and damage to strata.</em>
Answer:
bacteria, archaea, eukaryota
Answer:
Differential equations capture the vectors of thr rate of change, which are found experimentally to be tangent to the configuration space of a system.
Explanation:
