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ehidna [41]
4 years ago
5

Please help ASAP

Mathematics
1 answer:
krok68 [10]4 years ago
6 0
C should be the answer
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Students in Mr. Rivas’ class were practicing their multiplication skills by rolling three 6-sided number cubes. Chris rolled a 2
guajiro [1.7K]

Sorry wrote down the wrong thing the first time. Try doing 2 plus 3 times 5.

3 0
3 years ago
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Which algebraic expression represents “the difference of fifty-four and seven times a number”? 54 minus 7 n StartFraction 54 Ove
VMariaS [17]

Answer: 54-7n

Step-by-step explanation:

When we talk about mathematical language, the <u>difference </u>between two numbers, quantities or terms is the <u>substraction operation.</u>

For example, the <u>difference</u> between a and b is:

a-b

On the other hand, if we read a numer c <u>times</u> a number n, this means both numbers are multiplied.

For example:

c <u>times</u> n is:

(c)(n)

So, according to the explained above, “the difference of fifty-four and seven times a number n” is:

54-7n

8 0
3 years ago
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Click the words to go to the link
PilotLPTM [1.2K]
Answer : C

The perimeter is all the sides added up, lets check C.

C states that 2 sides have a measure of 9, and two sides have a measure of 4.

9+9 = 18  4+4 = 8

18+8 = 26

The question states that the perimeter is 26 so this makes sense, now lets check our area.

Area = width * length

9 * 4 = 36

The question states that the area must equal 36, and it does therefore you correct answer is C
5 0
3 years ago
Santa Claus loves to drop presents out of his sled during Christmas. The height above the ground of one present after t seconds
Ahat [919]

Answer:

The present was 300 feet above ground 5 seconds after being thrown.

6.47 seconds passed before the present hit the ground.

Step-by-step explanation:

We have the following quadratic function

h(t) = -16t^{2} - 20t + 800

Which determines the height of the present.

Determine when the present was 300 feet above the ground.

This is when h(t) = 300. So

h(t) = -16t^{2} - 20t + 800

300 = -16t^{2} - 20t + 800

-16t^{2} - 20t + 500 = 0

This is t = -6.25 and t = 5. There are no negative time instants. So the present was 300 feet above ground 5 seconds after being thrown.

Determine how many seconds passed before the present hit the ground.

This is t when h(t) = 0

h(t) = -16t^{2} - 20t + 800

-16t^{2} - 20t + 800 = 0

t = 6.47

6.47 seconds passed before the present hit the ground.

5 0
3 years ago
What is the solution to the system of equation -4+3y=-3
Shalnov [3]

Answer:

\huge\boxed{\sf y = 1/3}

Step-by-step explanation:

<h3>Given equation:</h3>

-4 + 3y = -3

Add 4 to both sides

3y = -3 + 4

3y = 1

Divide 3 to both sides

<h3>y = 1/3</h3>

\rule[225]{225}{2}

7 0
2 years ago
Read 2 more answers
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