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Levart [38]
2 years ago
8

How much carbon would be needed to make 8.8g of carbon dioxide?​

Chemistry
1 answer:
PIT_PIT [208]2 years ago
7 0
The calculation for such a question can be achieved via Avogadro hypothesis

We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms

Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..

44g/mole = 6.023 ※10^23 CO2 molecules

=> 1g = (6.023/44) ※10^23 CO2 molecules

==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….

Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
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Describe how to do an experiment to show that when you dissolve salt in water the salt is still there.
Alex17521 [72]

Answer:

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Explanation:

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2 years ago
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solid carbon dioxide, iodine, arsenic, and naphthalene

Explanation:

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3 0
2 years ago
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Nataly_w [17]
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4 0
2 years ago
A sample of octane (c8h18 that has a mass of 0.750 g is burned in a bomb calorimeter. as a result, the temperature of the calori
timurjin [86]
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Heat of the combustion reaction = mC(T2-T1)
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7 0
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Read 2 more answers
Mg2OH has how many unique elements?<br> A. <br> 4<br> B. <br> 2<br> C. <br> 3<br> D. <br> 5
frutty [35]

Answer:

Magnesium hydroxide has 3 unique elements.

Explanation:

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(This is only an opinion of mathematical science to me, I don't have complete understanding of this subject either, good luck.)

5 0
3 years ago
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