Question

Question 1. In the following equation for the alpha decay of bismuth-214, supply the missing element that correctly completes the equation.
Question 2. Complete the following equations by correctly matching the appropriate product.

Answer 1

Q1. TI (210/81Thallium)
Q2.
The answers are opposite from each other

Answer 2

Answer: a) Tl (Thallium)

b) $^{210}_{84}\textrm{Bi}\rightarrow ^{206}_{82}\textrm{Pb}+^4_2\textrm{He}$

$^{218}_{84}\textrm{Bi}\rightarrow ^{214}_{82}\textrm{Pb}+^4_2\textrm{He}$

$^{214}_{84}\textrm{Bi}\rightarrow ^{210}_{82}\textrm{X}+^4_2\textrm{He}$

Explanation:

Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

General representation of an element is given as:   $_Z^A\textrm{X}$

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

Total mass on reactant side = total mass on product side

214= A + 4 , A = 210

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

83= Z + 2, Z = 81

$^{214}_{83}\textrm{Bi}\rightarrow ^{A}_{Z}\textrm{X}+^4_2\textrm{He}$

b)

1. $^{210}_{84}\textrm{Bi}\rightarrow ^{206}_{82}\textrm{Pb}+^4_2\textrm{He}$

Total mass on reactant side = total mass on product side

210= A + 4 , A = 206

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

84= Z + 2, Z = 82

2. $^{218}_{84}\textrm{Bi}\rightarrow ^{214}_{82}\textrm{Pb}+^4_2\textrm{He}$

Total mass on reactant side = total mass on product side

218= A + 4 , A = 214

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

84= Z + 2, Z = 82

3. $^{214}_{84}\textrm{Bi}\rightarrow ^{210}_{82}\textrm{X}+^4_2\textrm{He}$

Total mass on reactant side = total mass on product side

214= A + 4 , A = 210

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

84= Z + 2, Z = 82