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zaharov [31]
3 years ago
7

Which statement describes what happens to the DNA in the process shown? A. Some of the DNA is destroyed, so each daughter cell h

as less DNA than the parent cell. B. The DNA in the parent cell is copied, so the parent cell and the daughter cells all have DNA. C. Some daughter cells get their DNA from the parent cell, but others need to make copies of the DNA. D. The existing DNA in the parent cell is equally distributed between four daughter cells.
Chemistry
1 answer:
kolbaska11 [484]3 years ago
7 0

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What is the mass, in grams, 6.5 mol of sodium nitrate (nano3)? please show all work?
ladessa [460]
Mass is the property of a physical body and the resistance to acceleration when a net force is applied on the body.  
The atomic mass of sodium (Na) is = 22.98 
The atomic mass of nitrate (N) is = 14.00 
The atomic mass of oxygen (O) is = 15.99  
The sodium nitrate (NaNO3) consists of the atomic masses of Na+N+(O)3 = 85 grams  
Therefore, the mass of 6.5 mol of sodium nitrate is = 6.5 * 1 mol of NaNO3 
 = 6.5 * (85) 
 = 552.50 grams
6 0
3 years ago
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Covalent Bonds <br><br> How many covalent bonds can Nitrogen atoms make ?
notsponge [240]
A nitrogen atoms can make 3 covalent bonds because it has three unpaired electrons

6 0
3 years ago
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What do alkali metals react bad with
solmaris [256]

Explanation:

what do you mean by "bad"

6 0
2 years ago
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HELPPP!!! what is the volume (in liters) of a 5.72 gram sample of 02 at STP? (Hint: remember to change grams of oxygen to moles
Alona [7]

Answer:

4L

Explanation:

To obtain the volume of O2 at stp, first, we need to determine the number of mole of O2.

From the question given above,

Mass of O2 = 5.72g

Molar Mass of O2 = 32g/mol

Number of mole =Mass/Molar Mass

Number of mole of O2 = 5.72/32

Number of mole of O2 = 0.179 mole

Now, we can calculate the volume of O2 at stp as follow:

1 mole of a gas occupy 22.4L at stp.

Therefore, 0.179 mole of O2 will occupy = 0.179 x 22.4 = 4L

Therefore, the volume occupied by the sample of O2 is 4L

7 0
3 years ago
Which step in the free-radical chlorination of methane do you expect to be the most exothermic? attempt this problem without loo
stiks02 [169]

The termination step of the free-radical chlorination of methane is the most stable one among all three steps.

The free-radical substitution reaction between chlorine and methane features three major steps:

Initiation, during which chlorine molecules undergo homolytic fission to produce chlorine free radicals. Ultraviolet radiations are typically applied to supply the energy required for breaking the chlorine-chlorine single bonds. The initiation step is thus <em>endothermic</em>.

Propagation, a process in which chlorine free radicals react with methane molecules and remove a hydrogen atom from the alkane to produce hydrogen chloride and an alkyl radical e.g., \cdot \text{CH}_3. The carbon-containing free radical would react with chlorine molecules to produce chloromethane and yet another chlorine free radical. This process can well repeat itself to chlorinate a significant number of methane molecules.

Termination. Free radicals combine to produce molecules. For example, two chlorine free radicals would combine to produce a chlorine molecule, whereas two alkyl free radicals would combine to produce an alkane with two-carbon atoms in its backbone.

Chemical processes that increase the stability of a substance reduces its chemical potential energy. Energy conserves, thus such processes would also release energy equal to the potential energy lost in quantity. Free radicals are unstable and- as seen in the propagation step- compete readily with neutral molecules for their electrons. The propagation step keeps the number of free radicals constant and is therefore more exothermic than the initiation step. The termination step reduces the number of free radicals, increase the stability of the system by the greatest extent, and is therefore the most exothermic step among the three.

3 0
3 years ago
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