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liq [111]
4 years ago
11

the student measured the volume of water as 80.0 mL. she discovered that the actual volume was 80.1 mL. is her results ac urate

why or why not

Chemistry
2 answers:
Oksana_A [137]4 years ago
8 0
Yes, the more decimal places in a number mean that it is more accurate :3
adoni [48]4 years ago
8 0

<u>Answer:</u> The result of the student measured is not accurate.

<u>Explanation:</u>

Accuracy is defined as the closeness of a measured value to a standard or known value.

For Example: If the mass of a substance is 50 kg and one person weighed 48 kg and another person weighed 55 kg. Then, the weight measured by first person is more accurate.

Precision is defined as the closeness of two or more measurements to each other.

For Example: If you weigh a given substance five times and you get 1.8 kg each time. Then the measurement is said to be precise.

Level of precision is determined by the maximum number of decimal places.

We are given:

Actual volume = 80.1 mL

Measured value = 80.0 mL

As, the measure value is 0.1 mL less than the true value. The level of precision is very high in this case. So, the measured value is not accurate.

Hence, the result of the student measured is not accurate.

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Calculate the morality of each of the following solutions: a. 15.4 g KCl in 289.2 mL solution b. 14.4 g of CaCl2 in 0.614 L solu
Nesterboy [21]
The answer is:
a. 0.712 M
b. 0.210 M
c. 0.336 M

Molarity is a measure of the concentration of solute in a solution.
It can be expressed as moles of solute ÷ volume of solution:
c = n ÷V
where:
c - concentration of solute,
n - moles of solute
V - volume of solution

n can be expressed as:
<span>n = m ÷ Mr
</span>where:
<span>n - moles of solute
</span>m - mass of solute
Mr - relative molecular mass

a. We know volume:
V = 289.2 mL = 0.2892 L
We need n and c.

n = m ÷ Mr
m = 15.4 g
Mr (<span>KCl) = 74.55 g/mol
n = </span>15.4 g ÷ <span>74.55 g/mol
n = 0.206 mol</span>

Thus, 
c = 0.206 mol ÷ <span>0.2892 L
c = 0.712 mol/L = 0.712 M

</span>b. We know volume:
V = 0.614 L
We need n and c.

n = m ÷ Mr
m = 14.4 g
Mr (CaCl₂<span>) = 110.98 g/mol
n = </span>14.4 g ÷ <span>110.98 g/mol
n = 0.129 mol</span>

Thus, 
c = 0.129 mol ÷ <span>0.614 L
c = 0.210 mol/L = 0.210 M
</span>
c. We can use formula:
m₁V₁ = m₂V₂
<span>m₁ = 3 M
</span><span>V₁ = 28 mL= 0.028 L
</span><span>m₂ = ?
</span><span>V₂ = 0.250 L
</span>Thus:
3 M × 0.028 L = m₂× <span>0.250 L
</span> m₂ = 0.336 M
4 0
3 years ago
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