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liq [111]
3 years ago
11

the student measured the volume of water as 80.0 mL. she discovered that the actual volume was 80.1 mL. is her results ac urate

why or why not

Chemistry
2 answers:
Oksana_A [137]3 years ago
8 0
Yes, the more decimal places in a number mean that it is more accurate :3
adoni [48]3 years ago
8 0

<u>Answer:</u> The result of the student measured is not accurate.

<u>Explanation:</u>

Accuracy is defined as the closeness of a measured value to a standard or known value.

For Example: If the mass of a substance is 50 kg and one person weighed 48 kg and another person weighed 55 kg. Then, the weight measured by first person is more accurate.

Precision is defined as the closeness of two or more measurements to each other.

For Example: If you weigh a given substance five times and you get 1.8 kg each time. Then the measurement is said to be precise.

Level of precision is determined by the maximum number of decimal places.

We are given:

Actual volume = 80.1 mL

Measured value = 80.0 mL

As, the measure value is 0.1 mL less than the true value. The level of precision is very high in this case. So, the measured value is not accurate.

Hence, the result of the student measured is not accurate.

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Reason:
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2) In present case, the reaction involved is: 
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2 years ago
Most of the nadh that delivers electrons to the electron transport chain comes from which of the following processes?
Neko [114]
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4 0
3 years ago
A sample of CaCO3 (molar mass 100. g) was reported as being 30. percent Ca. Assuming no calcium was present in any impurities, c
natka813 [3]

Answer:

Approximately 75%.

Explanation:

Look up the relative atomic mass of Ca on a modern periodic table:

  • Ca: 40.078.

There are one mole of Ca atoms in each mole of CaCO₃ formula unit.

  • The mass of one mole of CaCO₃ is the same as the molar mass of this compound: \rm 100\; g.
  • The mass of one mole of Ca atoms is (numerically) the same as the relative atomic mass of this element: \rm 40.078\; g.

Calculate the mass ratio of Ca in a pure sample of CaCO₃:

\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} = \frac{40.078}{100} \approx \frac{2}{5}.

Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be \rm 30 \% \times 100\; g = 30\; g of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio \displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} \approx \frac{2}{5}:

\begin{aligned} m\left(\mathrm{CaCO_3}\right) &= m(\mathrm{Ca})\left/\frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)}\right. \cr &\approx 30\; \rm g \left/ \frac{2}{5}\right. \cr &= 75\; \rm g \end{aligned}.

In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:

\displaystyle 100\%\times \frac{m\left(\mathrm{CaCO_3}\right)}{m(\text{sample})} = \frac{75}{100} = 75\%.

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Answer:

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A compound is made up of two or more different atoms. A particular compound is unique/uniform in its composition and doesn't share its particular composition with another compound. For example, carbon monoxide (CO) is made up of one atom of carbon and one atom of oxygen while carbon dioxide (CO₂) is made up of one atom of carbon and two atoms of oxygen.

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Finger [1]

Answer:

Cu(OH)2 + 2HCl → CuCl2 + 2H2O

5 0
2 years ago
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