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maw [93]
3 years ago
11

Anions are formed when *

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
6 0
Anions are negative ions so it’s when an atom gains electrons
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Is silicon a compound yes or no​
Crazy boy [7]

Answer: Yes

Explanation: Silicon is never found as a free element naturally, meaning it always occurs with other elements.

4 0
3 years ago
How much energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°c and completely vaporize the sample?
natta225 [31]

The 7160 cal energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°C and completely vaporize the sample.

Calculation,

Given data,

Mass of the ice = 10 g

Temperature of ice =  0. 0°C

  • The ice at 0. 0°C is to be converted into water at 0. 0°C

Heat required at this stage = mas of the ice ×latent heat of fusion of ice

Heat required at this stage = 10 g×80 = 800 cal  

  • The temperature of the water is to be increased from 0. 0°C to 100. 0°C

Heat required for this = mass of the ice×rise in temperature×specific heat of water

Heat required for this  = 10 g×100× 1 = 1000 cal

  • This water at  100. 0°C  is to be converted into vapor.

Heat required for this = Mass of water× latent heat

Heat required for this  = 10g ×536 =5360 cal

Total energy or heat required = sum of all heat = 800 +1000+ 5360  = 7160 cal

to learn more about energy

brainly.com/question/7185299

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6 0
1 year ago
Which of the following is the best example of kinetic energy being transformed into potential energy?
galben [10]

Answer:

The correct answer is A

Explanation:

That water stops moving once it gets to the dam and turns into potential energy

5 0
3 years ago
How does melting order relate to melting point?
KatRina [158]

Answer:

I think A.

Explanation:I say A because of the substance melting the quicking does have the highest melting point because its the highest.

5 0
2 years ago
ODIO POD
miss Akunina [59]

Answer:

\boxed{\text{40 mol Al}}

Explanation:

            Al₂O₃ ⟶ 2Al + 3O₂

n/mol:     20

\text{Moles of Al} = \text{20 mol Al$_{2}$O$_{3}$}\times \dfrac{\text{2 mol Al}}{\text{1 mol Al$_{2}$O$_{3}$}}= \textbf{40 mol Al}\\\text{You can produce }\boxed{\textbf{40 mol Al}}

8 0
3 years ago
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