MFe: 56 g/mol
..........
56g ----- 1 mol
5g ------- X
X = 5/56 = 0,089 moles of Fe
56g ----- 6,02×10²³ atoms
5g ------- X
X = (5×6,02×10²³)/56
X = 0,5375×10²³ = 5,375×10²² atoms of Fe
:•)
Answer:
600.7 moles
Explanation:
Applying,
PV = nRT................... Equation 1
Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.
make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 190 atm, V = 35 L, T = 135 K
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
n = (190×35)/(135×0.082)
n = 600.7 moles of xygen
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