calcium reacts with fluorine to produce calcium fluoride. how does oxidation and reduction take place in this reaction?
1 answer:
The oxidation is occurring on Calcium ions as it release one electron and reduction will be occurring on fluorine ion as it accepts one electron.
<u>Explanation:</u>
An element will undergo oxidation and form a positive ion on releasing one or more electrons from its valence shell. While reduction is occurred in a chemical reaction, then the element will be forming a negative ion with the acceptance of one or more electrons in its valence shell.
So in the given process of calcium fluoride, the one electron from the valence shell of calcium will be released making it as ions and this is termed as oxidation process. This one electron will be getting accepted by the fluorine ion and thus it will convert to
ions. This process of acceptance of electrons is termed as reduction.
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Answer:
Up to
.
Explanation:
The equation for this reaction: is indeed balanced.
Notice that the coefficient of is
while that of
is
.
Therefore, each unit of this reaction would consume units of
while producing
units of
. In other words, this reaction would produce three times as much
as it consumes
.
If all that of
molecules are actually consumed through this reaction, three times as many
molecules would be produced. That corresponds to
of
molecules.