calcium reacts with fluorine to produce calcium fluoride. how does oxidation and reduction take place in this reaction?
1 answer:
The oxidation is occurring on Calcium ions as it release one electron and reduction will be occurring on fluorine ion as it accepts one electron.
<u>Explanation:</u>
An element will undergo oxidation and form a positive ion on releasing one or more electrons from its valence shell. While reduction is occurred in a chemical reaction, then the element will be forming a negative ion with the acceptance of one or more electrons in its valence shell.
So in the given process of calcium fluoride, the one electron from the valence shell of calcium will be released making it as ions and this is termed as oxidation process. This one electron will be getting accepted by the fluorine ion and thus it will convert to
ions. This process of acceptance of electrons is termed as reduction.
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Answer : The number of ice cubes melt must be, 13
Explanation :
First we have to calculate the mass of water.
Density of water = 1.00 g/mL
Volume of water = 650 mL
Now we have to calculate the heat released on cooling.
Heat released on cooling =
where,
m = mass of water = 650 g
c = specific heat capacity of water =
= final temperature =
= initial temperature =
Now put all the given values in the above expression, we get:
Heat released on cooling =
Heat released on cooling = 78793 J = 78.793 kJ (1 J = 0.001 kJ)
As, 1 ice cube contains 1 mole of water.
The heat required for 1 ice cube to melt = 6.02 kJ
Now we have to calculate the number of ice cubes melted.
Number of ice cubes melted =
Number of ice cubes melted =
Number of ice cubes melted = 13.1 ≈ 13
Therefore, the number of ice cubes melt must be, 13