I pretty sure it true I’m not completely sure
Answer:
CHCI₃
Explanation:
Chloroform, IUPAC name, trichloromethane, is organic compound with the molecular formula CHCl₃. It is colorless and sweet-smelling liquid having high density which is produced on a large scale precursor of PTFE , and for various refrigerants .
Chloroform , is a powerful euphoriant , anxiolytic , anesthetic and sedative when inhaled or ingested .
The answer for the following problem is mentioned below.
- <u><em>Therefore the final temperature of the gas is 740 K</em></u>
Explanation:
Given:
Initial pressure of the gas (
) = 1.8 atm
Final pressure of the gas (
) = 4 atm
Initial temperature of the gas (
) = 60°C = 60 + 273 = 333 K
To solve:
Final temperature of the gas (
)
We know;
From the ideal gas equation;
we know;
P × V = n × R × T
So;
we can tell from the above equation;
<u> P ∝ T</u>
(i.e.)
<em> </em>
<em> = constant</em>
= 
Where;
= initial pressure of a gas
= final pressure of a gas
= initial temperature of a gas
= final temperature of a gas
= 
=
= 740 K
<u><em>Therefore the final temperature of the gas is 740 K</em></u>
<span>187.56 g/mol
That is the answer</span>
Answer is: the average atomic mass 217.606 amu.
Ar₁= 203.973 amu; the average atomic mass of isotope.
Ar₂ = 205.9745 amu.
Ar₃ = 206.9745 amu.
Ar₄ = 207.9766 amu.
ω₁ = 1.40% = 0.014; mass percentage of isotope.
ω₂ = 24.10% = 0.241.
ω₃ = 22.10% = 0.221.
ω₄ = 57.40% = 0.574.
Ar = Ar₁ · ω₁+ Ar₂ · ω₂ + Ar₃ · ω₃ + Ar₄ · ω₄.
Ar = 203.973 amu · 0.014 + 205.9745 amu · 0.241 + 206.9745 amu · 0.221 + 207.9766 amu · 0.574.
Ar = 2.855 amu + 49.632 amu + 45.741 amu + 119.378 amu.
Ar = 217.606 amu.
But abundance of isotopes is greater than 100%.
It should be lead, with the fourth isotope weighs 207.9766 amu and an abundance of 52.40.
