<span>To
solve this we assume that the gas is an ideal gas. Then, we can use the ideal
gas equation which is expressed as PV = nRT. At number of moles the value of PV/T is equal to some constant. At another
set of condition of temperature, the constant is still the same. Calculations
are as follows:</span>
P1V1/T1 = P2V2/T2
P2 = P1 (V1) (T2) / (T1) (V2)
P2 = 475 kPa (4 m^3) (277 K) / (290 K) (6.5 m^3)
P2 = 279.20 kPa
Therefore, the changes in the temperature and the volume lead to a change in the pressure of the system which is from 475 kPa to 279.20 kPa. So, there is a decrease in the pressure.
The Earth's structural zones (S-Zones) are the lithosphere, asthenosphere, mesosphere, inner core, and outer core.
C-Zone S-Zone What are they like?
Core Inner Core Found about 2,900 kilometers below
the Earth's surface. It is about 2,300 kilometers thick
Answer:
The volume on the tank is 6, 20 L
Explanation:
We use the formula PV=nRT. We convert the units of pressure in kPa into atm and temperature in Celsius into Kelvin:
0°C=273K
101,325kPa---1 atm
275kPa --------x=(275kPax 1 atm)/101,325kPa= 2,71 atm
PV=nRT --> V=nRT/P
V= 0,750 mol x 0,082 l atm /K mol x 273 K/ 2, 71 atm= <em>6, 20 L</em>
Answer:
I think it is the second one
Explanation:
Because what the cold water did to the table salt, is that it separated its molecules dissolving the salt.
even though the rock salt was in hot water it was a bigger particle. But the big difference was only because the water temperature ️.
Changing the position of the substituents in an organic molecule will often result in a different chemical compound. If the structure of the molecule changes but it still has the same molecular formula, i.e., the same number of each atom, then this is called a structural isomer. However, it is possible to change the position of a substituent and the structure of the molecule remain unchanged. This would most likely occur in symmetric molecules.
CH₃ - CH₂ - CH₂ - CH₂ - OH 1-butanol
CH₃ - CH₂ - CH - CH₃ 2 - butanol
|
OH
Looking at the two structures above, the position of the -OH was moved from the 1-carbon to the 2-carbon, resulting in two different molecules. These are structural isomers. However, we can also move the -OH group without changing the molecule.
CH₃ - CH₂ - CH - CH₃ 2-butanol
|
OH
CH₃ - CH - CH₂ - CH₃ 2-butanol
|
OH
In the above structure, it appears that the -OH group was moved from the 2-carbon to the 3-carbon, but since this molecule is symmetrical, the 2- and 3-carbons are equivalent. Therefore, swapping substituents has no effect on the structure of the molecule and these are equivalent.
