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mafiozo [28]
4 years ago
5

Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are

thermodynamically unfavorable (nonspontaneous), but proceed when they are coupled with other reactions.
Reaction A: Pi+glucose⟶glucose-6-phosphate+H2OΔG=13.8 kJ/mol

Reaction B: Pi+fructose-6-phosphate⟶fructose-1,6-bisphosphate+H2OΔG=16.3 kJ/mol

Reaction C: ATP+H2O⟶ADP+PiΔG=−30.5 kJ/mol

Select every unfavorable reaction.

reaction B
reaction C
reaction A

Select every set of coupled reactions where the overall reaction is favorable.

reactions B and C
reactions A and B
reactions A and C

What is the net change in free energy if one set of reactions from the previous question is coupled so that the overall reaction is favorable? Note that if you selected more than one set of coupled reactions as favorable in the previous question, you may enter the net change for any one of your selected sets.
Chemistry
1 answer:
mote1985 [20]4 years ago
4 0

Answer:

Unfavorable reactions: Reaction A and Reaction B.

Coupled reactions favorable: Reactions B and C and Reactions A and C.

Net change:

Reactions B and C : -14.2kJ/mol

Reactions A and B : 30.1kJ/mol

Reactions A and C: -16.7kJ/mol

Explanation:

A reaction is thermodynamically favorable (spontaneous) if ΔG < 0. Thus, the unfavorable reactions -ΔG > 0- are:

Reaction A and reaction B.

When reaction C is coupled with reaction B and reaction A the chemical equation is:

ATP + fructose-1,6-phosphate ⟶ ADP + fructose-1,6-bisphosphate

ΔG = 16.3 - 30.5 = -14.2 kJ/mol

ATP + glucose ⟶ ADP + glucose-6-phosphate

ΔG = 13.8 - 30.5 = -16.7 kJ/mol

The coupled reaction of A and B has a change in free energy of:

ΔG = 13.8 + 16.3 = 30.1 kJ/mol

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During a chemical reacion, an iron atom beacme the ion Fe+2. what happened to the iron atom?
galben [10]

Answer:

That iron atom is oxidized. It loses two electrons.

Explanation:

Compare the formula of an iron atom and an iron(II) ion:

  • Iron atom: \mathrm{Fe};
  • Iron(II) ion: \mathrm{Fe^{2+}}.

The superscript +2 in the iron(II) ion is the only difference between the two formulas. This superscript indicates a charge of +2 on each ion. Atoms and ions contain protons. In many cases, they also contain electrons. Each proton carries a positive charge of +1 and each electron carries a charge of -1. Atoms are neutral for they contain an equal number of protons and electrons.

Protons are located at the center of atoms inside the nuclei. They cannot be gained or lost in chemical reactions. However, electrons are outside the nuclei and can be gained or lost. When an atom loses one or more electrons, it will carry more positive charge than negative charge. It will becomes a positive ion. Conversely, when an atom gains one or more electrons, it becomes a negative ion.

An iron atom \mathrm{Fe} will need to lose two electrons to become a positive iron(II) ion \mathrm{Fe^{2+}} with a charge of +2 on each ion. That is:

\rm Fe \to Fe^{2+} + 2\;e^{-}.

  • Oxidation is Losing one or more electrons;
  • Reduction is Gaining one or more electrons.

This definition can be written as the acronym OILRIG. (Khan Academy.)

In this case, each iron atom loses two electrons. Therefore the iron atoms here are oxidized.

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3 years ago
Find the volume of a gas at standard pressure if its volume at 1.9 atm is 80 ml?
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Answer:

1.5 × 10² mL

Explanation:

Step 1: Given data

  • Initial pressure of the gas (P₁): 1.9 atm
  • Initial volume of the gas (V₁): 80 mL
  • Final pressure of the gas (P₂): 1.0 atm (standard pressure)
  • Final volume of the gas (V₂): ?

Step 2: Calculate the final volume of the gas

For an ideal gas, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 1.9 atm × 80 mL/1.0 atm

V₂ = 1.5 × 10² mL

Since the pressure decreased, the volume of the gas increased.

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