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mafiozo [28]
3 years ago
5

Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are

thermodynamically unfavorable (nonspontaneous), but proceed when they are coupled with other reactions.
Reaction A: Pi+glucose⟶glucose-6-phosphate+H2OΔG=13.8 kJ/mol

Reaction B: Pi+fructose-6-phosphate⟶fructose-1,6-bisphosphate+H2OΔG=16.3 kJ/mol

Reaction C: ATP+H2O⟶ADP+PiΔG=−30.5 kJ/mol

Select every unfavorable reaction.

reaction B
reaction C
reaction A

Select every set of coupled reactions where the overall reaction is favorable.

reactions B and C
reactions A and B
reactions A and C

What is the net change in free energy if one set of reactions from the previous question is coupled so that the overall reaction is favorable? Note that if you selected more than one set of coupled reactions as favorable in the previous question, you may enter the net change for any one of your selected sets.
Chemistry
1 answer:
mote1985 [20]3 years ago
4 0

Answer:

Unfavorable reactions: Reaction A and Reaction B.

Coupled reactions favorable: Reactions B and C and Reactions A and C.

Net change:

Reactions B and C : -14.2kJ/mol

Reactions A and B : 30.1kJ/mol

Reactions A and C: -16.7kJ/mol

Explanation:

A reaction is thermodynamically favorable (spontaneous) if ΔG < 0. Thus, the unfavorable reactions -ΔG > 0- are:

Reaction A and reaction B.

When reaction C is coupled with reaction B and reaction A the chemical equation is:

ATP + fructose-1,6-phosphate ⟶ ADP + fructose-1,6-bisphosphate

ΔG = 16.3 - 30.5 = -14.2 kJ/mol

ATP + glucose ⟶ ADP + glucose-6-phosphate

ΔG = 13.8 - 30.5 = -16.7 kJ/mol

The coupled reaction of A and B has a change in free energy of:

ΔG = 13.8 + 16.3 = 30.1 kJ/mol

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3 years ago
The steps in every scientific investigation must_______________________.
Marizza181 [45]

Answer:

B. begin with a hypothesis

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6 0
3 years ago
what is the balanced equation when copper metal is placed in a solution when platnium ii chloride is placed. what is the equatio
koban [17]

Answer:

Cu~+~PtCl_2->Pt~+~CuCl_2

Explanation:

In this case, we can start with the <u>formula of Platinum (II) Chloride</u>. The cation is the atom at the left of the name (in this case Pt^+^2) and the anion is the atom at the right of the name (in this case Cl^-). With this in mind, the <u>formula would be</u> PtCl_2.

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Cu~+~PtCl_2->

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A~+~BC->AB~+~C

With this in mind, the reaction would be:

Cu~+~PtCl_2->Pt~+~CuCl_2

I hope it helps!

5 0
3 years ago
Chemistry
postnew [5]

There are 48.72 g  Fluorine ions

<h3>Further explanation </h3>

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison

%F in CaF₂ :

\tt \%F=\dfrac{2.Ar~F}{MW~CaF_2}\times 100\%\\\\\%F=\dfrac{2.19}{78}\times 100\5=48.72\%

mass of Fluorine :

\tt 48.72\%\times 200=97.44~g

So mass Fluorine ions(2 ions F in CaF₂⇒Ca²⁺+2F⁻) :

\tt =\dfrac{97.44}{2}=48.72~g

7 0
2 years ago
Which law relates to the ideal gas law?
professor190 [17]

<u>Answer:</u> The law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

<u>Explanation:</u>

There are 4 laws of gases:

  • <u>Boyle's Law:</u> This law states that pressure is inversely proportional to the volume of the gas at constant temperature.  

Mathematically,

P_1V_1=P_2V_2

  • <u>Charles' Law:</u> This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

  • <u>Gay-Lussac Law:</u> This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

  • <u>Avogadro's Law:</u> This law states that volume is directly proportional to number of moles at constant temperature and pressure.

Mathematically,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

Hence, the law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

8 0
3 years ago
Read 2 more answers
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