Answer:
Lead(II) sulfate
Explanation:
This looks like a double displacement reaction, in which the cations change partners with the anions.
The possible products are
Pb(NO₃)₂ (aq)+ Na₂SO₄(aq) ⟶PbSO₄(?) + 2NaNO₃(?)
To predict the product, we must use the solubility rules. Two important ones for this question are:
- Salts containing Group 1 elements are soluble.
- Most sulfates are soluble, but PbSO₄ is an important exception.
Thus, NaNO₃ is soluble and PbSO₄ is the precipitate.
I think it would be Kriptonite
Answer:
oook
hi I am so sorry sorry sorry sorry I don't no answer
Explanation:
but you follow me and give me brainliest ok by by by by
M CH₃COOH: 12u×2 + 1u×4 + 16u×2 =<u> 60u</u>
m 9CH₃COOH: 60u×9 = <u>540u</u>
<em>(1u ≈ 1,66·10⁻²⁴g)</em>
-----------------------------
1u ------- <span>1,66·10⁻²⁴g
540u ---- X
X = 540</span>×<span>1,66·10⁻²⁴g
<u>X = 896,4</u></span><span><u>·10⁻²⁴g
</u></span>
