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patriot [66]
3 years ago
8

How do base-isolators, the rubber and steel pads under some buildings, reduce earthquake damage?

Physics
2 answers:
nika2105 [10]3 years ago
8 0

They absorb the energy of seismic waves.

Explanation:

Base - isolators, rubber and steel pads under buildings reduces earthquake damage by absorbing the energy of seismic waves.

  • Earthquakes are produced by the sudden release of energy within the earth which causes displacement and sharp movement on earth surface.
  • There are four main types of waves that are propagated by seismic waves which wrecks havoc.
  • Understanding the waves and their properties has been useful in designing earthquake resistant structures.
  • Base-isolators, rubber and steel pads helps to absorb seismic waves.
  • When seismic waves are absorbed, they are cut off.
  • This way they cannot cause damage.

learn more:

Earthquake brainly.com/question/6520403

#learnwithBrainly

lisabon 2012 [21]3 years ago
4 0

Answer:

D

Explanation:

it just is

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Engineers are designing a curved section of a highway. If the radius of curvature of the curve is 194 m, at what angle should th
Brums [2.3K]

Answer:

The banking angle is 23.84 degrees.

Explanation:

Given that,

Radius of the curve, r = 194 m

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On the banked curve, the centripetal force is balanced by the force of friction such that,

mg\ tan\theta=\dfrac{mv^2}{r}

tan\theta=\dfrac{v^2}{rg}

tan\theta=\dfrac{(29)^2}{194\times 9.8}

\theta=23.84^{\circ}

So, the banking angle is 23.84 degrees. Hence, this is the required solution.    

5 0
3 years ago
According to the Guinness Book of World Records, the longest home run ever measured was hit by Roy "Dizzy" Carlyle in a minor-le
Alina [70]
Range of a projectile motion is given by
R = v cos θ / g (v sin θ + sqrt(v^2 sin^2 θ + 2gy_0)); where R = 188m, θ = 41°, g = 9.8m/s^2, y_0 = 0.9

188 = v cos 41° / 9.8 (v sin 41° + sqrt(v^2 sin^2 41° + 2 x 9.8 x 0.9)) = 0.07701(0.6561v + sqrt(0.4304 v^2 + 17.64)) = 0.05053v + 0.07701sqrt(0.4304v^2 + 17.64)
0.07701sqrt(0.4304v^2 + 17.64) = 188 - 0.05053v
0.005931(0.4304v^2 + 17.64) = 35344 - 19v + 0.002553v^2
0.002553v^2 + 0.1046 = 35344 - 19v + 0.002553v^2
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5 0
3 years ago
A magnetic compass is placed near an insulated copper wire. When the wire is connected to a battery and a current is created, th
lawyer [7]

Explanation:

When the wire is connected to a battery, the compass needle moves and changes its position. This happens because the needle magnetizes the copper wire, thus,  creating a force.

While the current in the wire produces a magnetic field and exerts a force on the needle. The insulation on the wire becomes energized and exerts a force on the needle. Hence, the compass needle moves and changes its position.

6 0
3 years ago
the magnitude of the magnetic field at point p for a certain electromagnetic wave is 2.21. What is the magnitude of the elctic f
vesna_86 [32]

Answer:

6.63\times 10^8\ N/C

Explanation:

Given that,

The magnitude of magnetic field, B = 2.21

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Put all the values,

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So, the magnitude of the electric field is equal to 6.63\times 10^8\ N/C.

7 0
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balu736 [363]

Answer:

Hindi ko po alam

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