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3 years ago

8

How do base-isolators, the rubber and steel pads under some buildings, reduce earthquake damage?

2 answers:

nika2105 [10]3 years ago

8 0

They absorb the energy of seismic waves.

Explanation:

Base - isolators, rubber and steel pads under buildings reduces earthquake damage by absorbing the energy of seismic waves.

Earthquakes are produced by the sudden release of energy within the earth which causes displacement and sharp movement on earth surface.
There are four main types of waves that are propagated by seismic waves which wrecks havoc.
Understanding the waves and their properties has been useful in designing earthquake resistant structures.
Base-isolators, rubber and steel pads helps to absorb seismic waves.
When seismic waves are absorbed, they are cut off.
This way they cannot cause damage.

learn more:

Earthquake brainly.com/question/6520403

#learnwithBrainly

lisabon 2012 [21]3 years ago

4 0

Answer:

D

Explanation:

it just is

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An airplane whose air speed is 527 mi/hr covers a distance of 907 miles in 2.25 hrs. How strong was the head wind against it?

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Answer:

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2 years ago

What would the electrostatic force be for two 0.005C charges 50m apart?

irakobra [83]

Answer:

90 N

Explanation:

The electrostatic force between two charges is given by:

$F=k\frac{q_1 q_2}{r^2}$

where

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In this problem we have

q1 = q2 = 0.005 C

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So the electrostatic force is

$F=(9\cdot 10^9 N m^2 C^{-2})\frac{(0.005 C)^2}{(50 m)^2}=90 N$

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3 years ago

Unpolarized light with intensity 370 W/m2 passes first through a polarizing filter with its axis vertical, then through a second

vampirchik [111]

To solve this problem it is necessary to apply the concepts given by Malus regarding the Intensity of light.

From the law of Malus intensity can be defined as

$I' = \frac{I_0}{2} cos^2 \theta$

Where

$\theta =$ Angle From vertical of the axis of the polarizing filter

$I_0 =$ Intensity of the unpolarized light

The expression for the intensity of the light after passing through the first filter is given by

$I = \frac{I_0}{2}$

Replacing we have that

$I = \frac{370}{2}$

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Re-arrange the equation,

$I'= \frac{I_0}{2}cos^2\theta$

Re-arrange to find \theta

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$\theta = cos^{-1}(\sqrt{\frac{2*138}{370}})$

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3 years ago

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natka813 [3]

Answer:

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Explanation:

Given:

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Gravitational force G = 6.67 × 10⁻¹¹

Find:

Speed of the satellite.

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Radius r = √[GMm / F]

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