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2 years ago

URGENT HELP! How is it that two moving objects can have a net momentum of zero?

Physics

2 answers:

Zielflug [23.3K]2 years ago

8 0

Answer:

because they may not actually be moving be just percieved as so

Explanation:

kirill [66]2 years ago

4 0

Answer:

i think that maybe there arent moving but there on something thats moving

Explanation:

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A diver leaves the end of a 4.0 m high diving board and strikes the water 1.3s later, 3.0m beyond the end of the board. Consider

shutvik [7]

Answer:

4.0 m/s

Explanation:

The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.

Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is

$d=v_x t$

where here we have

d = 3.0 m is the horizontal distance covered

vx is the horizontal velocity

t = 1.3 s is the duration of the fall

Solving for vx,

$v_x = \frac{d}{t}=\frac{3.0 m}{1.3 s}=2.3 m/s$

Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by

$y(t) = h + v_y t - \frac{1}{2}gt^2$

where

h = 4.0 m is the initial height

vy is the initial vertical velocity

We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy

$0=h+v_y t - \frac{1}{2}gt^2\\v_y = \frac{0.5gt^2-h}{t}=\frac{0.5(9.8 m/s^2)(1.3 s)^2-4.0 m}{1.3 s}=3.3 m/s$

So now we can find the magnitude of the initial velocity:

$v=\sqrt{v_x^2+v_y^2}=\sqrt{(2.3 m/s)^2+(3.3 m/s)^2}=4.0 m/s$

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2 years ago

Where can you find your carotid pulse to take your heart rate?

Nesterboy [21]

Answer: In your right wrist

Explanation:

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3 years ago

How long does it for a car to cover 100 miles at 60 mi/hr? Use one of the following equations:

Mazyrski [523]

1 hour and 40 minutes

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2 years ago

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What frequency fapproach is heard by a passenger on a train moving at a speed of 18.0 m/s relative to the ground in a direction

Sergio039 [100]

Answer:

The frequency is 302.05 Hz.

Explanation:

Given that,

Speed = 18.0 m/s

Suppose a train is traveling at 30.0 m/s relative to the ground in still air. The frequency of the note emitted by the train whistle is 262 Hz .

We need to calculate the frequency

Using formula of frequency

$f'=f(\dfrac{v+v_{p}}{v-v_{s}})$

Where, f = frequency

v = speed of sound

$v_{p}$ = speed of passenger

$v_{s}$ = speed of source

Put the value into the formula

$f'=262\times(\dfrac{344+18}{344-30})$

$f'=302.05\ Hz$

Hence, The frequency is 302.05 Hz.

7 0

2 years ago

You and your friends find a rope that hangs down 19m from a high tree branch right at the edge of a river. You find that you can

tangare [24]

Answer:

Explanation:

Given

length of rope $L=19\ m$

velocity while running $v=2\ m/s$

when the person jumps off the bank and hang on the rope then we can treat the person as pendulum with Time period T which is given by

$T=2\pi \sqrt{\frac{L}{g}}$

$T=2\pi \sqrt{\frac{19}{9.8}}$

$T=2\pi \times 1.392$

$T=8.74\ m/s$

Greatest Possible distance will be covered when person reaches the other extreme end of assumed pendulum (velocity=zero)

therefore he must hang on for 0.5 T time

$time=0.5\times 8.74=4.37\ s$

5 0

2 years ago